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Travka [436]
4 years ago
5

Which part of the light waves does color correspond to?

Physics
2 answers:
MariettaO [177]4 years ago
7 0

Answer:

The colour of visible light depends on its wavelength. These wavelengths range from 700 nm at the red end of the spectrum to 400 nm at the violet end. Visible light waves are the only electromagnetic waves we can see. We see these waves as the colors of the rainbow.

Explanation:

My name is Ann [436]4 years ago
3 0

Answer:

Visible Light Waves

Explanation:

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A motorboat approaches you head-on and sounds one short blast. how do you signal that you agree to let it pass on your port (lef
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The blast made by the vessel's driver is telling you that he intends to pass by your left side. If you agree with his intention, you will respond by sounding one short blast in return. If you are not in agreement with this move or you do not really understand the intention of the driver, you will give the danger signal which is five short rapid blasts.
6 0
3 years ago
A car is initially moving at 35 km/h along a straight highway. To pass another car, it speeds up to 135 km/h in 10.5 seconds at
Aleks04 [339]
Acceleration = (velocity final-velocity initial)/ time
where
velocity final = 135 km/hr x 1 hr /3600 s x 1000m/1km
                     = 37.5 m/s
velocity initial = 35 km/hr x  1hr /3600 s x 1000 m/1 km
                      =  9.72 m/s
a) acceleration = 2.646 m/s^2
b) acceleration in g units  = (2.646m/s^2)/(9.8m/s^2)
                                              = 0.27 units

6 0
4 years ago
If there is 8 g of a substance before a physical change , how much will there be afterwards?
Dimas [21]
A substance undergoing a physical change will still weigh the same even after the change. This is in accordance to the law of conservation of mass which states that mass is neither created nor destroyed. so an 8 g substance remains of the same weight even after undergoing a physical change.
8 0
4 years ago
Read 2 more answers
The triceps muscle in the back of the upper arm is primarily used to extend the forearm. Suppose this muscle in a professional b
bagirrra123 [75]

To solve this problem it is necessary to address the concepts related to Torque as a function of the force and distance where it is applied and the moment of inertia from which the torque, moment of inertia and angular acceleration are related.

By definition the torque is defined as

\tau = F*r

Where,

\tau = Torque

F = Force

r = Radius

For our values we have:

\tau = F*r

\tau = (1.75*10^3)(2.8*10^{-2})

\tau = 49Nm

Consequently the calculation of the moment of inertia would then be given by the relationship

\tau = I\alpha

I=\frac{\tau}{\alpha}

Replacing with our values

I = \frac{49}{150}

I = 0.322Kg.m^2

The moment of inertia of the boxer's forearm 0.322Kg.m^2

4 0
3 years ago
A car is traveling at 50 mi/h when the brakes are fully applied, producing a constant deceleration of 44 ft/s2. What is the dist
elena55 [62]

Answer:

Distance, d = 61.13 ft

Explanation:

It is given that,

Initial speed of the car, u = 50 mi/h = 73.34 ft/s

Finally, it stops i.e. v = 0

Deceleration of the car, a=-44\ ft/s^2

We need to find the distance covered before the car comes to a stop. Let the distance is s. It can be calculated using third law of motion as :

v^2-u^2=2as

s=\dfrac{v^2-u^2}{2a}

s=\dfrac{0-(73.34\ ft/s)^2}{2\times -44\ ft/s^2}

s = 61.13 ft

So, the distance covered by the car before it comes to rest is 61.13 ft. Hence, this is the required solution.

4 0
4 years ago
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