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wel
3 years ago
14

Jack purchased a car for $22,000. The bank gave him an annual interest rate of 4.3%. He will make monthly payments for 6 years (

or 72 months). Jack followed these steps to determine his approximate monthly payments. Read through the steps, and then choose Jack’s approximate monthly payment from the drop‐down menu.
1.Calculate the interest rate per period.
0.043
12
≈ 0.00358
2.Add 1 to the interest rate per period.
1 + 0.00358 = 1.00358
3. Raise the number calculated in step 2 to the negative power of the number of loan payments to be made, and then subtract this number from 1.
1.00358-(12)(6) = 1.00358-72 ≈ 0.7731
1 − 0.7731 = 0.2269
4. Divide the interest rate per period by the number calculated in step 3.
0.00358
0.2269
≈ 0.0158
5. Multiply the quotient from step 4 by the principal.
Jack’s monthly payment ≈
Complete step 5 to determine Jack's monthly payment for the loan. Round to the nearest cent.
Mathematics
2 answers:
daser333 [38]3 years ago
7 0

Answer:

The answer is B, 347.60.

Step-by-step explanation:

LenaWriter [7]3 years ago
5 0

Answer:

347.60

Step-by-step explanation:

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There are 5000 undergraduates registered at a certain college. Of them, 448 are taking one course, are taking two courses, 675 a
olga55 [171]

Answer:

Step-by-step explanation:

Hello!

There are some values missing, so I'll find the probability distribution using others as example. Afterwards you can calculate the ones corresponding to this exercise following the same steps.

Considering there are 5000 undergraduates registered in the college.

465 are taking one course

658 are taking two courses

566 are taking three courses

1877 are taking four courses

1344 are taking five courses

90 are taking six courses

First you have to define the variable of interest. To identify it you have to ask yourself the following question: what is the characteristic of this population that is being measured?

The answer is "the number of courses an undergraduate is taking" and this will be the study variable X

X can take values from 1 to 6 courses.

To calculate the probability of each value of X, you have to divide the "number of students taking Xi courses" by "total number of students registered in the college"

For

X=1

P(1)= 465/5000= 0.093

X=2

P(2)= 658/5000= 0.1316

X=3

P(3)= 566/5000= 0.1132

X=4

P(4)= 1877/5000= 0.3754

X=5

P(5)= 1344/5000= 0.2688

X=6

P(6)= 90/5000= 0.018

For this to be a probability distribution the following condition should be met:

F(X)= ∑P(X) = 1

In this example: 0.093 + 0.1316 + 0.1132 + 0.3754 + 0.2688 + 0.018 = 1

I hope this helps!

7 0
3 years ago
Which of the following are valid names for the given triangle? Check all that apply.
vfiekz [6]
When naming triangles we name them by the letters on each corner so only answers with T, A, and X in them are correct, so TAX, XTA, and AXT
6 0
3 years ago
Read 2 more answers
HELP ME QUICK: Suppose AB has one endpoint at A(0, 0). If (5, 3) is the midpoint of AB, what are the coordinates of point B?
DiKsa [7]

Answer:

<h3>           B(10, 6)</h3>

Step-by-step explanation:

If P is midpoint of AB and:  A(0,\,0)\,,\quad P(5,\,3)\,,\quad B(x_B,\,y_B)

then:

x_P-x_A=x_B - x_P\qquad\quad\ \wedge\qquad y_P-y_A=y_B - y_P\\\\ 5-0=x_B-5\qquad\quad\wedge\qquad 3-0=y_B -3\\\\ x_B=5+5\qquad\qquad\wedge\qquad\ \ y_B=3+3 \\\\ {}\quad x_B=10\qquad\qquad\wedge\qquad\qquad \ y_B=6

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3 years ago
Write the equation of the line in fully simplified slope-intercept form.
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3 years ago
Nancy found that x=1 is one solution to the quadratic equation (x 2)2=a. what is the value of a?
trasher [3.6K]

The value of the a in the quadratic equation is 4.

According to the statement

we have given that the x = 1 and the given equation is  (2x)^2=a

And we have to find the value of A here.

So, For this purpose, we know that the

A quadratic equation is an equation of the second degree, meaning it contains at least one term that is squared.

And the given quadratic equation is

(2x)^2 = a

we know that the x  = 1 and put the value of x in it then

(2(1))^2= a

(2)^2= a

a  = 4.

Now for rechecking of the value, put a = 4 in the given equation then

(2x)^2 = a

Put a  = 4

Then

(2x)^2 = 4

2x = 2

And the value of x become

x = 1.

Which equal to the given value of the x which is 1.

So, The value of the a in the quadratic equation is 4.

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