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Vitek1552 [10]
2 years ago
6

Solve each proportion 3 = 72 – 7​

Mathematics
1 answer:
Vanyuwa [196]2 years ago
4 0
1. 504=3x
x=168

2. 64=20m
m=3.2
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Which of the following best describes the solution to the system of equations below?
OverLord2011 [107]

Answer: OPTION A

Step-by-step explanation:

The equation of the line in slope-intercept form is:

y=mx+b

Where m is the slope and b the y-intercept.

Solve for y from each equation:

\left \{ {{5y=-4x+7} \atop {10y=-8x+14}} \right.\\\\\left \{ {{y=\frac{-4}{5}x+\frac{7}{5}} \atop {y=\frac{-8}{10}x+\frac{14}{10}}} \right.\\\\\left \{ {{y=\frac{-4}{5}x+\frac{7}{5}} \atop {y=\frac{-4}{5}x+\frac{7}{5}}} \right.

As you can see the slope and the y-intercept of each equation are equal, this means that both are the exact same line. Therefore, you can conclude that the system has infinitely many solutions.

3 0
3 years ago
PLEASE HELP AS SOON AS POSSIBLE
Temka [501]
Store 1 because there’s a greater variety !!!
8 0
1 year ago
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ABCD is a trapezium AD and BC are parallel
Orlov [11]

Part (a)

<h3>Answer:  12.1</h3>

-----------------------

Work Shown:

We'll apply the sine rule since we have a known opposite side of AB = 10 and an unknown hypotenuse we want to find BD.

Focus on triangle ABD

sin(angle) = opposite/hypotenuse

sin(D) = AB/BD

sin(56) = 10/x

x*sin(56) = 10

x = 10/sin(56)

x = 12.062179

x = 12.1

Make sure your calculator is in degree mode.

===================================================

Part (b)

<h3>Answer:  15.1</h3>

-----------------------

Work Shown:

Draw an xy coordinate grid.

Place point A at the origin (0,0).

Point B is 10 units above this, so B is at (0,10).

Point C is at (18,10) since we move 18 units to the right of B.

Point D is at approximately (6.745085, 0). The 6.745085 is from solving tan(56) = 10/x for x.

Refer to the diagram below.

Apply the distance formula for the points C and D.

C = (x_1,y_1) = (18,10)\\\\D = (x_2,y_2) \approx (6.745085,10)\\\\

d = \text{ distance from C to D}\\\\d = \sqrt{ (x_1-x_2)^2+(y_1-y_2)^2}\\\\d \approx \sqrt{ (18-6.745085)^2+(10-0)^2}\\\\d \approx \sqrt{ 226.673112 }\\\\d \approx 15.055667\\\\d \approx 15.1\\\\

Segment CD is roughly 15.1 cm long.

3 0
2 years ago
Read 2 more answers
Hello everyone, Agent Mothman here. I hate math, not as much as i hate Zim.. but I still hate it. Please help me out, my dad is
Lana71 [14]
The answer would be A because you would take all of your answers and 1 by 1 multiply it by0.35 and it will give you the answer of $330.43 

7 0
3 years ago
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A randomized trial tested the effectiveness of diets on adults. Among 36 subjects using Diet 1, the mean weight loss after a yea
seropon [69]

Answer:

The 95%  confidence interval is

           0.45 <  \mu_1 - \mu_2  < 5.35

Step-by-step explanation:

From the question we are told that

   The first sample size is  n_1   =  36

   The first  sample mean is  \= x_1  =  3.5

   The first standard deviation is  \sigma_1  =  5.9 \ pounds

   The second  sample size is n_2 =  36

    The second  sample mean is  \= x_2 =  0.6

    The second  standard deviation is \sigma  =  4.4

Generally the degree of freedom is mathematically represented as

     df =  \frac{ [ \frac{s_1^2 }{n_1 }  + \frac{s_2^2 }{n_2} ]^2 }{ \frac{1}{(n_1 - 1 )} [ \frac{s_1^2}{n_1} ]^2 + \frac{1}{(n_2 - 1 )} [ \frac{s_2^2}{n_2} ]^2  }

=>  df =  \frac{ [ \frac{5.9^2 }{34 }  + \frac{4.4^2 }{34} ]^2 }{ \frac{1}{(34 - 1 )} [ \frac{5.9^2}{34} ]^2 + \frac{1}{(34- 1 )} [ \frac{4.4^2}{ 34} ]^2  }

=>  df =63

Generally the standard error is mathematically represented as

      SE =  \sqrt{ \frac{s_1 ^2 }{n_1}  + \frac{s_2^2 }{ n_2 } }

=>  SE =  \sqrt{ \frac{ 5.9 ^2 }{ 36 }  + \frac{ 4.4^2 }{36} }

=>  SE = 1.227

From the question we are told the confidence level is  95% , hence the level of significance is    

      \alpha = (100 - 95 ) \%

=>   \alpha = 0.05

Generally from the t distribution table the critical value  of   at a degree of freedom of is  

     t_{\frac{\alpha }{2}, 63  } =  1.998

Generally the margin of error is mathematically represented as

        E =  t_{\frac{\alpha }{2}, 63  } *  SE

=>    E =  1.998 * 1.227

=>    E =  2.45

Generally 95% confidence interval is mathematically represented as  

      (\= x_1 - \x_2) -E <  \mu

 => (3.5  - 0.6) - 2.45 <  \mu_1 - \mu_2  < (  3.5  - 0.6)  + 2.45

=>   0.45 <  \mu_1 - \mu_2  < 5.35

     

8 0
2 years ago
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