Answer:
Following are the solution to the given question:
Explanation:
Since a procedure has the Read10 parameter, the 10 characters from the input file are stored in the BYTE array as myString. The LOOP instruction, which includes indirect addressing and also the call to the ReadChar method, please find the attached file of the procedure:
Answer:
a. Remove the affected servers from the network.
Explanation:
An organization's incident response process (IRP) can be defined as all of the process involved in the cleanup and recovery of data when they fall victim to an attack or cybersecurity breach. The incident response process comprises of six (6) important stages and these are;
1. Preparation.
2. Detection and analysis (identification).
3. Containment.
4. Eradication.
5. Recovery.
6. Review of incident activities.
When an organization's IRP prioritizes containment over eradication and an incident is discovered, where an attacker outside the organization installed a crypto-currency mining software on the organization's web servers. Given the organization's stated priorities, the cybersecurity engineer should remove the affected servers from the network.
A containment process is focused on taking steps to eliminate or contain the attack. It basically involves acting swiftly in response to the attack, so as to prevent it from spreading across board or in order to mitigate the damage already caused.
In this context, the cybersecurity engineer should remove the affected servers from the network in accordance with the organization's IRP priority (containment).
<em>Furthermore, he could take a step further to contain the attack by installing a firewall and updating their policies in the Intrusion Prevention System (IPS) of the organization. </em>
Answer:
def leap_year(y):
if y % 4 == 0:
return 1
else:
return 0
def number_of_days(m,y):
if m == 2:
return 28 + leap_year(y)
elif m == 1 or m == 3 or m == 5 or m == 7 or m == 8 or m ==10 or m == 12:
return 31
elif m == 4 or m == 6 or m == 9 or m == 11:
return 30
def days(m,d):
if m == 1:
return 0 + d
if m == 2:
return 31 + d
if m == 3:
return 59 + d
if m == 4:
return 90 + d
if m == 5:
return 120 + d
if m == 6:
return 151 + d
if m == 7:
return 181 + d
if m == 8:
return 212 + d
if m == 9:
return 243 + d
if m == 10:
return 273 + d
if m == 11:
return 304 + d
if m == 12:
return 334 + d
def days_left(d,m,y):
if days(m,d) <= 60:
return 365 - days(m,d) + leap_year(y)
else:
return 365 - days(m,d)
print("Please enter a date")
day=int(input("Day: "))
month=int(input("Month: "))
year=int(input("Year: "))
choice=int(input("Menu:\n1) Calculate the number of days in the given month.\n2) Calculate the number of days left in the given year.\n"))
if choice == 1:
print(number_of_days(month, year))
if choice == 2:
print(days_left(day,month,year))
Explanation:
Hoped this helped
Answer:
465 ways
Explanation:
Atleast 1 girl and 1 boy
Possible combinations :
1 girl ; 3 boys = 6C1 ; 6C3
2 girls ; 2 boys = 6C2 ; 6C2
3 girls ; 1 boy = 6C3 ; 6C1
(6C1 * 6C3) + (6C2 * 6C2) + (6C3 * 6C1)
Combination formula:
nCr = n! ÷ (n-r)!r!
We can also use a calculator :
6C1 = 6
6C3 = 20
6C2 = 15
Hence,
(6C1 * 6C3) + (6C2 * 6C2) + (6C3 * 6C1)
(6 * 20) + (15 * 15) + (20 * 6)
120 + 225 + 120
= 465 ways
