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Sav [38]
3 years ago
7

Show that each expression is equivalent to 2x. Assume x is a positive real number 6x^3/(3√27x^6)

Mathematics
1 answer:
AveGali [126]3 years ago
6 0

Answer and explanation

We have given equation \frac{6x^3}{\sqrt[3]{27x^6}}

We have to prove that after operation it will be equal to 2x

We know that cube root of 27 is 3

And cube root of x^6 is x^2

So we can write the expression \frac{6x^3}{\sqrt[3]{27x^6}}=\frac{6x^3}{3x^2}=2x

So after doing operation on the given expression the result will be 2x

Hence proved

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