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3 years ago

What is 6.362 in word form

Mathematics

1 answer:

-BARSIC- [3]3 years ago

5 0

Six and three hundred thirty two thousandths

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Kruka [31]

Answer:

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Step-by-step explanation:

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2 years ago

Read 2 more answers

What is the sum of the last four terms of the series 7+9+11+...21

Sidana [21]

For sake of convenience, reverse the series, then it would be:

21,19,17.....7

a=21, d = -2,

s(4) = 4/2 (21+15)

s(4)=2(36)

s(4) = 72

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4 years ago

3/2b+5=20−b pls help solve

victus00 [196]

Answer:

b=6

Step-by-step explanation:

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3 years ago

Prove 2√(x) + 1/√(x + 1) <= 2√(x+1) for all x in [0,inf)

EleoNora [17]

Start by multiplying each side of the inequality by $\sqrt{x + 1}$ and simplifying:

$2 \sqrt x + \frac{1}{\sqrt{x+1}} \leq 2 \sqrt{x + 1}$
$(2 \sqrt x + \frac{1}{\sqrt{x+1}})(\sqrt{x + 1}) \leq (2 \sqrt{x + 1})(\sqrt{x + 1})$
$2 \sqrt{x(x + 1)} + 1 \leq 2(x + 1)$
$2 \sqrt{x^2 + x} + 1 \leq 2x + 2$
$2 \sqrt{x^2 + x} \leq 2x + 1$
$\sqrt{x^2 + x} \leq x + \frac{1}{2}$

From here, we can square both sides to get

$x^2 + x \leq (x + \frac{1}{2})^2$
$x^2 + x \leq x^2 + x + \frac{1}{4}$
$0 \leq \frac{1}{4}$ , which is always true.

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3 years ago

The endpoints of CD are C(−4, 7) and D(0,−3).

tino4ka555 [31]

Midpoint =(\frac{x_{2}+x_{1}}{2},\frac{y_{2}+y_{1}}{2})

Answer:

Midpoints of line CD are (-2,2).

Step-by-step explanation:

The midpoints is given by

$Midpoint =(\frac{x_{2}+x_{1}}{2},\frac{y_{2}+y_{1}}{2})$