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Naily [24]
3 years ago
15

Solve the compound inequality. Graph the solution -2 ≤ 2x – 4 < 4

Mathematics
1 answer:
Ulleksa [173]3 years ago
5 0
-2 \ \textless \ = 2x - 4 \ \textless \  4 

-2+4\ \textless \ 2x\ \textless \ 4+4&#10; &#10;  Add \ 4 \ to \ the \ whole \ equation 

&#10;2\ \textless \ 2x\ \textless \ 8&#10; &#10;  Simplify \ inequality 

1\ \textless \ x\ \textless \  \dfrac{8}{2} Divide \ the \ whole \ equation \ by \ 2 

&#10;1\ \textless \ x\ \textless \ 4&#10; &#10; = (1,4)
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If all city buses carry the same number of passengers, what is the least number of buses needed to carry 710 passengers? 5 10 11
noname [10]

The least number of buses needed to carry 710 passengers is 5.

Option A)5 is the correct answer.

<h3>What is the least number of buses needed to carry 710 passengers? </h3>

Given that;

  • Number of passengers n = 710
  • Least number of buses need B = ?

To get the least number of buses, we say;

Number of buses B = 710 ÷ 150

Number of buses B = 4.7 ≈ 5

The least number of buses needed to carry 710 passengers is 5.

Option A)5 is the correct answer.

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5 0
2 years ago
Given a and b are numbers, and a + b = 180, which
Anastasy [175]
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6 0
3 years ago
Jaime has 8/10 of a candy bar left over. He wants to split it into 1/3 pieces.
Valentin [98]

Answer:

2 pieces.

Step-by-step explanation:

To identify how many pieces he can split with 8/10 of a candy bar, divide 8/10 by 1/3.

<u>Divide 8/10 by 1/3:</u>

\frac{8}{10} / \frac{1}{3}=

<u>Find the Ricipricol, then flip the sign:</u>

\frac{8}{10} (\frac{3}{1} )=

<u>Multiply:</u>

<u />\frac{8}{10} (\frac{3}{1})=\frac{24}{10} =\frac{2.4}{1}

2.4 represents how many pieces of chocolate he can make with 8/10 of a candy bar.

However, 2.4 pieces can't be made, therefore he can only make 2 <u>full</u> pieces.

6 0
3 years ago
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