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Oksi-84 [34.3K]
3 years ago
12

What is the solution to the system of equations?

Mathematics
1 answer:
Elan Coil [88]3 years ago
5 0

Answer:

(7, 10.5)

Step-by-step explanation:

just going to use substitution here.

so you would substitute the y value in the equation x-2y=-14 with 2x-3.5.

it should look like: x-2(2x-3.5)=-14

solve the equation and you get x=7.

plug in 7 for x in either equation and you get y= 10.5.

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What is the answer to 1/4 - (-1/6)​
Aloiza [94]

Answer:

5/12

Step-by-step explanation:

1/4 + 1/6 = (6+4)/24 = 10/24 = 5/12

why +1/6?

because: - (-) = +

4 0
3 years ago
After 10 years, Hamid's account earned $300 in interest. If the interest rate (in decimal form) is 0.06, how much did Hamid init
tester [92]

Answer:

  • p = I/(rt)
  • p = $500

Step-by-step explanation:

To solve the equation I=prt for p, divide by its coefficient, rt. That gives ...

  p = I/(rt)

__

Now, to answer the question, you can substitute the given values for I, r, t and you have ...

  p = $300/(0.06·10) = $500

Hamid initially invested $500.

6 0
4 years ago
You have won the lottery and will receive 20 annual payments of $10,000 starting today. If you can invest these payments at 8.5%
xxTIMURxx [149]

Answer:

$102,677.20

Step-by-step explanation:

The present value of an annuity due is determined by the following expression:

PV = P+P*(\frac{1-(1+r)^{-n+1}}{r})

Where 'P' is the amount of each payment received, 'r' is the interest rate on the investment and 'n' is the number of yearly payments.

With 20 annual payments of $10,000 at a rate of 8.5%, the present value is:

PV = 10,000+10,000*(\frac{1-(1+0.085)^{-20+1}}{0.085})\\PV = 10,000+ 10,000*(9.26772)\\PV=\$102,677.20

The present value of your winnings is $102,677.20.

8 0
3 years ago
??????????????.??????
DIA [1.3K]
So in a cube, the width, length, and height are the same. Therefore, you have to find the cube root of 15.625 which is 2.5 and so the side length is 2.5
6 0
3 years ago
(X2)3<br> Power of a power rule
nalin [4]
2•3=6
I’m not for sure but used photomath
6 0
3 years ago
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