The distance covered by the hare and the tortoise in t seconds are 8t and 5t respectively. (Simple Speed-Distance-Time relation)
The tortoise gets a 510m headstart so at t=0 is 1490m.
The functions representing the distance of both of them from the finish line is,
F(x)=2000-8t,. for hare
G(x)=1490-5t,. for tortoise
Answer:
8
Step-by-step explanation:
If it stays as fraction the answer would be 7/14
Answer:
15y=x
Step-by-step explanation:
I believe the 4th one
an=145+an-1 and a1=20