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laiz [17]
3 years ago
7

Kuri spent a total of $68 on trading cards. His collection contains two types of cards. A pack of trading card A cost $4, and a

pack of trading card B cost $7. How many packs of each type of trading card were purchased if the total number of packs is 11
Mathematics
2 answers:
devlian [24]3 years ago
8 0
4a+7b=68 go to mathpapa
Gre4nikov [31]3 years ago
7 0
Let x = the number of packs for trading card A
Let y = the number of packs for trading card B

x + y = 11
4x + 7y = 68

Try and solve for y first
x = 11 - y
Substitute
4(11 - y) + y =68
Y =8 then x= 3
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kozerog [31]
9+10=?
9 = 3x3
10= 5x2
3 (from 3x3) x 5 (from 5x2) = 15
3 (from 3x3) x 2 (from 5x2) = 6
15+6=21
Therefore 9+10=21
5 0
3 years ago
Amelia made 3 1/3 pounds of trail mix. If she puts 2/3 of a pound into each bag, how many bags can Amelia fill? Write your answe
Neporo4naja [7]

Answer:

6

Step-by-step explanation:

Because ⅔ goes into 3 ⅓ 6 times.

7 0
3 years ago
Write an expression that is equivalent to 4(b+2)-3b
vekshin1
Ok so first we need to distribute so:
<span>=<span><span><span><span><span>(4)</span><span>(b)</span></span>+<span><span>(4)</span><span>(2)</span></span></span>+</span>−<span>3b
</span></span></span>=<span>4b+8+−3b
</span>So now that we've distrubuted that we are now going to Combine Like Terms:
<span>=<span><span><span>4b</span>+8</span>+<span>−<span>3b
</span></span></span></span><span>=<span><span>(<span><span>4b</span>+<span>−<span>3b</span></span></span>)</span>+<span>(8)
Finally your answer is:
</span></span></span><span>=<span>b+<span>8
I hope this helps you!</span></span></span>
6 0
3 years ago
Read 2 more answers
HURRY NEED HELP ASAP I WILL GIVE BRAINLIEST!!
Anuta_ua [19.1K]
Identify the angle variable to use.
Write an equation.
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7 0
3 years ago
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Amir is building a birdhouse that looks like a castle. The diagram shows the roof of the birdhouse. He plans to paint the roof r
Amiraneli [1.4K]

Answer:

The surface area is 0.64\ m^{2}

Step-by-step explanation:

we know that

The surface area of a square pyramid is equal to the area of the square base plus the area of its four lateral triangular faces.

so

SA=b^{2}+4[\frac{1}{2}(b)(l)]

we have

b=0.4\ m

l=0.6\ m

substitute the values

SA=0.4^{2}+4[\frac{1}{2}(0.4)(0.6)]=0.64\ m^{2}

4 0
3 years ago
Read 2 more answers
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