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4 years ago

Which best compares appointments and events in Outlook 2010

1 answer:

5 0

In Microsoft Outlook, there are differences between appointment and event. Appointment is defined as an activity that you schedule in your calendar which does not involve other people. Appointments can be scheduled to a certain duration in a day. Event is defined as an activity that you do with other people which lasts from 24 hours to longer.

Thus, from these descriptions, the best answer to the question is (C) appointments have a start and end time of day, and events do not.

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PLEASE HELP!! Would you ever try and get famous off of social media? Why or why not?

Alexxandr [17]

Answer:

Yes because u could gain a lot of money from it

Explanation:

With more money you have, the more you can give to charity, and the more you can relax

3 0

3 years ago

Read 2 more answers

Programming challenge description: Given a string comprising just of the characters (,),{,},[,] determine if it is well-formed o

nadezda [96]

Answer:

Employing Java language,

Explanation:

//for using stack data structure

import java.util.Stack;

//class definition

public class BracketMatch {

//function to find the string is well formed or not

public static boolean isWellFormed(String str) {

//variable to store the character value

char ch;

//check if the first character itself is the end of the brackets

if (str.charAt(0) == ')'||str.charAt(0) =='}'||str.charAt(0) ==']')

return false;

//creating a stack of character type

Stack<Character> stack = new Stack<Character>();

//iterating through the characters in string

for(int i=0; i < str.length(); i++) {

//storing the current character from the string in the variable

ch = str.charAt(i);

if(ch == '('||ch=='{'||ch=='[')

//if the character is starting of the brackets push it into stack

stack.push(ch);

else if(ch == ')')

//if it is closing bracket and the stack is empty then the string is not well formatted

if(stack.empty())

return false;

else if(stack.peek() == '(')

stack.pop();

else

return false;

else if(ch == '}')

if(stack.empty())

return false;

else if(stack.peek() == '{')

stack.pop();

else

return false;

}

//returning the stack content, if the string will be well formed the stack would be empty

//after all the operations

return stack.empty();

}

//main method

public static void main(String[] args) {

//calling function to find if the string is welll formatted or not

System.out.println(isWellFormed("{}"));

//calling function to find if the string is welll formatted or not

System.out.println(isWellFormed("([)]"));

}

5 0

4 years ago

What is information technology?

nirvana33 [79]

Information technology is the application of computers to store, retrieve, transmit and manipulate data, often in the context of a business or other enterprise.

7 0

3 years ago

The range of a finite nonempty set of $n$ real numbers $S$ is defined as the difference between the largest and smallest element

-Dominant- [34]

Answer: Hello your question is poorly written attached below is the well written question

answer:

a) Determine ( compute ) the difference between the max and minimum value. determine the Min and max values using 1.5n comparisons

time efficiency = θ( n )

b) A(n-1) - A(0)

time efficiency = θ( 1 )

Explanation:

a) An unsorted array

To find the maximum and minimum values scan the array of elements , then determine ( compute ) the difference between the max and minimum value. to determine the range. Alternatively determine the Min and max values using 1.5n comparisons

Algorithm's time efficiency = θ( n )

b) A sorted array

To determine the range, we will determine the difference between the first and last element i.e. A(n-1) - A(0)

time efficiency = θ( 1 )

7 0

3 years ago

List the seven basic internal components found in a computer tower

egoroff_w [7]

1. Motherboard (you plug all other components to it)
2. Processor (CPU)
3. Memory (RAM)
4. Graphics card
5. Sound card (sometimes integrated with motherboard)
6. Hard Disk Drive (HDD)
7. Power supply unit

6 0

4 years ago

Read 2 more answers