Answer:
0010
Explanation:
Serially left shifted means that the left most bit will enter the register first. The left most bit already stored in the register will move out of the sequence. The "bold" bits mentioned below highlight these left most bits:
Initial State of the Register:
0000
Group of bits entering:
1011
<u>First Clock Cycle:</u>
0000 <em>(This bold bit will move out)</em>
1011 <em>(This bold bit will move in from right side, shifting the whole sequence one place to the left).</em>
The resulting Sequence:
0001
<u>Second Clock Cycle:</u>
0001 <em>(This bold bit will move out)</em>
1011 <em>(This bold bit will move in from right side, shifting the whole sequence one place to the left).</em>
The resulting Sequence:
0010 <em>(Final Answer)</em>
Answer:
Explanation:
d(x) = -2x - 6
to find the inverse of a function, you need to follow these steps:
1. set d(x) = y
2. interchange the variables, so y becomes x and x becomes y
3. solve the equation for y
<u>step 1:</u> set d(x) = y
y = -2x -6
<u>step 2:</u> interchanging the variables
y = -2x - 6 turns into x = -2y - 6
<u>step 3:</u> solving for y
x = -2y - 6 < add 6 to both sides to get rid of it on the right
x + 6 = -2y < divide both sides by -2 to get y alone
x + 6 / -2 =
-2y / -2 = y
= y
so the inverse of the function is
Answer:
#include<iostream>//library inclusion
using namespace std;
int main()
{
int userInput;
do//start of do while loop
{
cout << "Enter a number less than a 100" << endl;
cin >> userInput;
if (userInput < 100) //condition
{
cout << "YOu entered less than a hundred: " << userInput << endl;
}
else
{
cout << "your number is greater than 100" << endl;
}
} while (userInput > 100);//condition for do while
return 0;//termination of int main
}
Explanation:
The program has been commented for you. The do-while loop enters the first loop regardless of the condition. Then after the first iteration, it checks for the condition. If the condition is being met, it will iterate through, again. Otherwise it will break out of the loop and land on the "return 0;" line. Which also happens to be the termination of the program in this case. The if-else condition is used for the user to see when prompted.
Answer:
A Tape Library
Explanation:
A tape library, sometimes called a tape silo, tape robot or tape jukebox, is a storage device that contains one or more tape drives, a number of slots to hold tape cartridges, a barcode reader to identify tape cartridges and an automated method for loading tapes. It Enables faster data migrations, reduce the complexity of and increase the frequency of backups, and streamline governance in a secure and cost-effective way.
Answer:
The code is given in C++ below
Explanation:
#include <iostream>
using namespace std;
int main()
{
float fv,pv,r,k,n,pmt,totalmoneyinvested;
pv=1000.00;
r=6/100;
k=12; //The value of k should be 12 for monthly installments
n=45;
pmt=250;
totalmoneyinvested=pv+(pmt*12*45); //The total money you invested
fv=pv*(1+r/k)*n*k+pmt*((1+r/k)*n*k-1)*(1+r/k)*r/k;
cout<<"Initial Investment:"<<" $"<<pv;
cout<<"\nRate Of Return:6%";
cout<<"\nLength of Time:"<<n<<"year";
cout<<"\nMonthly Payment:"<<" $"<<pmt;
cout<<"\nFinal Amount:"<<" $"<<fv;
cout<<"\nThe Money You Invested Is $"<<totalmoneyinvested<<" And The Final Amount Is $"<<fv;
return 0;
}
