1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Nata [24]
3 years ago
6

Need help i have been stuck on this problem

Mathematics
1 answer:
liberstina [14]3 years ago
4 0
The second one is correct
You might be interested in
What weight of dry substance is in 150g of a 3% substance solution? What weight of an 8% solution can we have with the same weig
Pavlova-9 [17]
The answers are: 4.5 g and 56.25 g respectively.

Since the first type of measurement in this question is weight or mass, I'll suppose that the percentage concentration is % mass/mass. For that type of concentration measurement, just multiply the percentage by the total mass to get the mass of the wanted material.
So 150 g * 3% = 150 g * 0.03 = 4.5g

For the 8% solution with the same amount of dry substance, use the ratio of percentages, multiplied by the mass of the first solution to get the wanted amount of new solution:
3/8 * 150 g = 56.35 g
5 0
3 years ago
SERIOUS MATH HELP PLEAZE<br> SHOW WORK OR AN EXPLANATION<br> HELPPPPPPPPPPPP
Tatiana [17]

Answer:

(X+8)(x-10

Step-by-step explanation:

The middle number is -2 and the last number is -80.

Factoring means we want something like

(x+_)(x+_)

Which numbers go in the blanks?

We need two numbers that...

Add together to get -2

Multiply together to get -80Try 8 and -10:

8+-10 = -2

8*-10 = -80

Fill in the blanks in

(x+_)(x+_)

with 8 and -10 to get...

(x+8)(x-10)

3 0
3 years ago
I am hating this quiz-
Alla [95]

Answer:

1. (A) Annuals only live for one year and will not return.

2. (B) when they appear between a character’s name and the character’s line

Step-by-step explanation:

Hope this helps!

3 0
2 years ago
Challenge
Katen [24]

Answer:

a). Distance from the surface of miner elevator=532 feet, Distance from the surface of equipment elevator=60 feet

b). The miner elevator is deeper since it is 472 feet deeper than the equipment elevator

Step-by-step explanation:

Equipment elevator speed=4 feet per second

Miner elevator=14 feet per second

Total time of miner elevator=(23+15)=38 seconds

Total time of equipment elevator=15 seconds

a). Distance from the surface of each elevator

Distance from the surface of miner elevator=Miner Speed×Miner Time

Distance=(14×38)=532 feet

Distance from the surface of equipment elevator=Equipment Speed×Equipment Time

Distance=(15×4)=60 feet

b). Which elevator is deeper

Distance from the surface of miner elevator=532 feet

Distance from the surface of equipment elevator= 60 feet

Difference=(532-60)=472 feet

The miner elevator is deeper since it is 472 feet deeper than the equipment elevator

5 0
4 years ago
Jason receives $19000 salary for working as a agent ​
d1i1m1o1n [39]

Answer:

$6992

Step-by-step explanation:

Simply do 36.8% of 19000 or 36.8 x 19000 to get 6992. That's the answer.

4 0
3 years ago
Other questions:
  • A student is assessing the correlation between the number of hours a plant receives sunlight and the height to which it grows. T
    13·2 answers
  • I need help ASAP please
    9·2 answers
  • Someone, please solve this, TYSM!
    5·1 answer
  • (4, 14.8), (8, 29.6), (12, 44.4) find the rate of change
    6·1 answer
  • What is (7-3b)(7+3b)
    6·1 answer
  • Samantha swam upstream for some distance in one hour. She then swam downstream the same river for the same distance in only 12 m
    14·1 answer
  • A school debate team has 4 girls and 6 boys. A total of 3 of the team members will be chosen to participate in the district deba
    6·1 answer
  • PLEASE HELP, EMERGENCY!!! <br><br><br> Don’t link any files!!!!
    8·1 answer
  • The vertex of a function is (-3, 0) and is a minimum. What is the axis of symmetry and how is it determined?
    15·1 answer
  • PLease help me i will give brainliest
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!