Answer:
x=−18
Step-by-step explanation:
Step 1: Simplify both sides of the equation.
12+2x=x−6
12+2x=x+−6
2x+12=x−6
Step 2: Subtract x from both sides.
2x+12−x=x−6−x
x+12=−6
Step 3: Subtract 12 from both sides.
x+12−12=−6−12
x=−18
-3 will be your slope and your y-intercept will be -2... equation i: y=-3x-2
Is b I already did that question like a lot of times is so easy trust me is b
(a) Compare your quadratic for h to the general quadratic ax² +bx +c. Perhaps you can see that ...
a = -16
b = 128
You use these numbers in the given formula to find the time when the ball is highest.
t = -b/(2a) = -128/(2(-16)) = 4 . . . . . . the time at which the ball is highest
(b) Evaluate the quadratic to find the height at t=4.
h = -16(4)² +128(4) +21
h = -256 +512 +21
h = 277
The maximum height of the ball is 277 ft.