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RideAnS [48]
4 years ago
11

5/7 is equal to A 42/63 B 45/63 C 35/63 D 54/63

Mathematics
1 answer:
GarryVolchara [31]4 years ago
5 0

Answer:

B 45/63

Step-by-step explanation:

5/7

Multiply the top and bottom by 9

5*9 =45

7*9 = 63

The fraction 45/63

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If m∠W = 105° and m∠Y = 75°, then m∠X = <br><br> Please show your work, so I know the process.
Paha777 [63]

Answer:

30°

Step-by-step explanation:

First we must know that the sum of the interior angles of a triangle sum up to 180°.  Furthermore, a straight line is also 180°.  By using these what we know we can determine what the value of m∠X is.

First we know that m∠W and m∠Z make up a straight line, since m∠W is 105° it follows that:

180° = m∠W + m∠Z

And so:

m∠Z = 180° - m∠W = 180°-105° = 75°

m∠Z = 75°

Now, we also know that the sum of m∠X + m∠Y + m∠Z = 180° and so:

m∠X = 180° - m∠Y - m∠Z

m∠X = 180° - 75° - 75° = 30°

Therefore, m∠X = 30°


7 0
4 years ago
Read 2 more answers
Find the area of each triangle.
CaHeK987 [17]

Answer:

4.) A = 1/2 bh

1/2 x 3 x 6

= 9in

8 0
3 years ago
Perform the indicated operation.
Vladimir [108]

\frac{2(a-3)}{(3+a)(3-a)}

Step-by-step explanation:

This can be written as;

\frac{8}{9-a^2} *\frac{a^2-6a+9}{4a^2-4a-24}

Perform factorization

9-a²=difference of squares formula

(3+a)(3-a)

4a²-4a-24

4(a²-a-6)

4(a²-3a+2a-6)

4(a(a-3)+2(a-3))

4((a+2)(a-3))

a²-6a+9

a²-3a-3a+9

a(a-3)-3(a-3)

(a-3)(a-3)

Rewrite the operation as;

\frac{8}{(3+a)(3-a)} *\frac{(a-3)(a-3)}{4((a+2)(a-3)}

cancel common to remain with;

\frac{2(a-3)}{(3+a)(3-a)}

Learn More

Factorization : brainly.com/question/11930808

Keywords : Operation

#LearnwithBrainly

7 0
3 years ago
In a parallel circuit, ET = 240 V, R = 47 kΩ, and XL = 50 kΩ. What is the reactive power?
Fittoniya [83]

Answer:

Reactive power is 1.152 VARs

Step-by-step explanation:

We are given that in a parallel circuit,E_{T}=240V,R=47kΩ and X_{L}=50kΩ.

reactive power means the dissipating power resulting from inductive and capacitive loads measured in volt-amperes reactive(VAR).Since our circuit has inductor only, reactive power will be power dissipated from inductor.

Current through inductor=\frac{E_{T}}{X_{L}} =\frac{240}{50}=4.8milli amps=0.0048 A

Reactive power = (current flowing through inductor)X (Voltage across inductor)

Hence reactive power = 0.0048 X 240=1.152 VARs

7 0
4 years ago
State the range of the numbers displayed in column x and column y. <br>xy <br> 15<br> 27<br>39
Masja [62]

We can not really tell in this question as you dont know the equation that is being used for the domain and range relationship but overall one should know that:

The set of values of the independent variable(s) for which a function or relation is defined as the domain of a function. Typically, this is the set of x-values that give rise to real y-values.

The range of a function is the complete set of all possible resulting values of the dependent variable (y, usually), after we have substituted the domain.

6 0
3 years ago
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