4x² - (2x + 3)²
4x² - (2x + 3)(2x + 3)
4x² - (2x(2x + 3) + 3(2x + 3))
4x² - (2x(2x) + 2x(3) + 3(2x) + 3(3))
4x² - (4x² + 6x + 6x + 9)
4x² - (4x² + 12x + 9)
4x² - 4x² - 12x - 9
-12x - 9
-3(4x) - 3(3)
-3(4x + 3)

8 0

3 years ago

What function was used to make that pattern

Semenov [28]

Answer:

Step-by-step explanation:

The differences in the terms of f(x) are + 3, + 5, + 7

Since the differences are not constant the relationship is not linear

Note the differences in the differences are + 2, + 2,

The second differences are constant indicating a quadratic relationship

Note the relationship between x and f(x)

x = 1 → 1² = 1 ← require to add 5, that is 1 + 5 = 6 ← value of f(x)

x = 2 → 2² = 4 ← require to add 5, that is 4 + 5 = 9 ← value of f(x)

x = 3 → 3² = 9 ← require to add 5, that is 9 + 5 = 14 ← value of f(x)

x = 4 → 4² = 16 ← require to add 5, that is 16 + 5 = 21 ← value of f(x)

Thus f(x) = x² + 5 → B

3 0

3 years ago

PLEASE SOLVE AND CHECK. SHOW COMPLETE SOLUTION

Alex17521 [72]

Solution:

$\sqrt{4x + 13} = x + 2$

First square both sides.

$= > ( \sqrt{4x + 13} ) ^{2} = (x + 2) ^{2}$

Now, square root and square gets cancel out in the LHS. And in the RHS, apply the identity: (a + b)² = a² + 2ab + b².

$= > 4x + 13 = {(x)}^{2} + 2 \times x \times 2 + (2) ^{2} \\ = > 4x + 13 = {x}^{2} + 4x + 4$

Now, transpose 4x and 4 to LHS.

$= > 4x - 4x + 13 - 4 = {x}^{2} \\$

Now, do the addition and subtraction.

$= > {x}^{2} = 9 \\ = > x = \sqrt{9} \\ = > x = ±3$

Answer:

x = ± 3

Hope you could understand.

If you have any query, feel free to ask.

3 0

2 years ago

HELP AGAINNNNN !!!!!!!!!!!!!!!!!!!

luda_lava [24]

Answer: A

Step-by-step explanation: 5*5=25 it is negative so the answer is -25

6 0

3 years ago