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ASHA 777 [7]
3 years ago
11

Volume of a pyramid: v = 1/3(area of base x (height surface area of a pyramid: a = 1/2(perimeter of base x (slant height + (area

of base a pyramid has a height of 4.7 in. and a slant height of 5.2 in. its base is a square with sides of 3.5 in. find the pyramid's volume and surface area.
Mathematics
2 answers:
stira [4]3 years ago
5 0
V= 1/3 LWH
1/3(3.5)(3.5)(4.7)
19.19 in ^3

SA= 2(3.5)(5.2)+(3.5)^2
48.65 in^2
icang [17]3 years ago
4 0

Answer:

Volume of Pyramid = 19.19 in^3\\

Surface Area of Pyramid  = 48.65 in^2\\\\

Step-by-step explanation:

Given

Height of the pyramid = 4.7 in\\

Slant height of the pyramid = 5.2 in\\

Base of pyramid is a square with side = 3.5 in\\

Volume of the pyramid

= \frac{1}{3} * (3.5 * 3.5) * (4.7)\\= 19.19 in^3\\

Surface area of the pyramid

=( \frac{1}{2} * (4 * 3.5) * 5.2) + ( 3.5 * 3.5)\\= 48.65 in^2\\

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