Question

Volume of a pyramid: v = 1/3(area of base x (height surface area of a pyramid: a = 1/2(perimeter of base x (slant height + (area of base a pyramid has a height of 4.7 in. and a slant height of 5.2 in. its base is a square with sides of 3.5 in. find the pyramid's volume and surface area.

Answer 1

V= 1/3 LWH
1/3(3.5)(3.5)(4.7)
19.19 in ^3

SA= 2(3.5)(5.2)+(3.5)^2
48.65 in^2

Answer 2

Answer:

Volume of Pyramid $= 19.19 in^3$

Surface Area of Pyramid  $= 48.65 in^2$

Step-by-step explanation:

Given

Height of the pyramid $= 4.7 in$

Slant height of the pyramid = $5.2 in$

Base of pyramid is a square with side $= 3.5 in$

Volume of the pyramid

$= \frac{1}{3} * (3.5 * 3.5) * (4.7)\\= 19.19 in^3$

Surface area of the pyramid

$=( \frac{1}{2} * (4 * 3.5) * 5.2) + ( 3.5 * 3.5)\\= 48.65 in^2$