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3 years ago

11

Volume of a pyramid: v = 1/3(area of base x (height surface area of a pyramid: a = 1/2(perimeter of base x (slant height + (area

of base a pyramid has a height of 4.7 in. and a slant height of 5.2 in. its base is a square with sides of 3.5 in. find the pyramid's volume and surface area.

2 answers:

stira [4]3 years ago

5 0

V= 1/3 LWH
1/3(3.5)(3.5)(4.7)
19.19 in ^3

SA= 2(3.5)(5.2)+(3.5)^2
48.65 in^2

icang [17]3 years ago

4 0

Answer:

Volume of Pyramid $= 19.19 in^3\\$

Surface Area of Pyramid $= 48.65 in^2\\\\$

Step-by-step explanation:

Given

Height of the pyramid $= 4.7 in\\$

Slant height of the pyramid = $5.2 in\\$

Base of pyramid is a square with side $= 3.5 in\\$

Volume of the pyramid

$= \frac{1}{3} * (3.5 * 3.5) * (4.7)\\= 19.19 in^3\\$

Surface area of the pyramid

$=( \frac{1}{2} * (4 * 3.5) * 5.2) + ( 3.5 * 3.5)\\= 48.65 in^2\\$

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