Let x and y be your two consecutive whole numbers
x < sqrt(142) < y
x^2 < 142 < y
So, we are looking for x and y such that x^2 < 142 and y^2 > 142.
The closest squared number to 142 is 144 = 12^2.
Next is 11^2 = 121.
11 and 12 are consecutive.
11^2 = 121 < 142 < 144 = 12^2
Thus, 11 and 12 are your numbers
Answer: the first one is 14 and the second one is 5
Step-by-step explanation:
One of the ways of dividing polynomials is by synthetic division
The divisor of the synthetic division is x + 5
<h3>How to determine the divisor of the division</h3>
From the question, we understand that:
Entry -5 is on the outside to the left of the shape
The entry represents the zero of the divisor.
Next, we set this entry to the variable (assume the variable is x)
So, we have:

Add 5 to both sides

Hence, the divisor of the synthetic division is x + 5
Read more about synthetic division at:
brainly.com/question/24662212
Answer:
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Step-by-step explanation:
<h3>✽ - - - - - - - - - - - - - - - ~<u>Hello There</u>!~ - - - - - - - - - - - - - - - ✽</h3>
➷ Find the greatest common factor of 9 and 12
It would be 3
9x/3 = 3x
-12/3 = -4
The correct option is C. 3(3x - 4)
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