Answer:
Since the calculated value of z= -1.496 does not fall in the critical region z < -1.645 we conclude that the new program is effective. We fail to reject the null hypothesis .
Step-by-step explanation:
The sample proportion is p2= 7/27= 0.259
and q2= 0.74
The sample size = n= 27
The population proportion = p1= 0.4
q1= 0.6
We formulate the null and alternate hypotheses that the new program is effective
H0: p2> p1 vs Ha: p2 ≤ p1
The test statistic is
z= p2- p1/√ p1q1/n
z= 0.259-0.4/ √0.4*0.6/27
z= -0.141/0.09428
z= -1.496
The significance level ∝ is 0.05
The critical region for one tailed test is z ≤ ± 1.645
Since the calculated value of z= -1.496 does not fall in the critical region z < -1.645 we conclude that the new program is effective. We fail to reject the null hypothesis .
I think it is B .... i dont know
Answer:
x = 5
Step-by-step explanation:
Using Pythagoras' identity in the right triangle.
The square on the hypotenuse is equal to the sum of the squares on the other 2 sides, that is
x² + 12² = 13², so
x² + 144 = 169 ( subtract 144 from both sides )
x² = 25 ( take the square root of both sides )
x =
= 5
Answer:
(2xy +x+y)(3xy² -y)
= 6x²y³ -2xy²+ 3x²y² -xy +3xy³ -y²
(xy+3x+2)(xy-9)
= X²y² -7xy+3x²y -27x-18
(x²+3xy-2)(xy+3)
= X³y + 3x² + 3x²y² +7xy -6
Step-by-step explanation:
For (xy+9y+2) and (xy-3)
(xy+9y+2) (xy-3)
= x²y² -3xy +9xy² -27y + 2xy -6
= x²y² -xy +9xy² -27y -6
For (2xy +x+y)(3xy² -y)
= 6x²y³ -2xy²+ 3x²y² -xy +3xy³ -y²
For (x-y)(x+3y)
= X² + 3xy -xy -3y²
= X² +2xy -3y²
For (xy+3x+2)(xy-9)
= X²y² -9xy +3x²y -27x+2xy -18
= X²y² -7xy+3x²y -27x-18
For (x²+3xy-2)(xy+3)
= X³y + 3x² + 3x²y² +9xy -2xy -6
= X³y + 3x² + 3x²y² +7xy -6