Ask question

Ask question

All categories

3 years ago

10

Simplify the expression below: 2(5x - 3y)

1 answer:

Len [333]3 years ago

8 0

Answer:

10x- 6y

Explanation:
Multiply the 2 with what’s inside the parentheses

You might be interested in

Solve the proportions

sasho [114]

Answer:

1.x = 80/8= 10

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

What is the value of x?

Mariulka [41]

Answer: x = 7

`Step-by-step explanation:

Because the figure shows two triangles that are similar. we can write and solve an equation of ratios:

9 cm 72 cm

----------- = -----------

3x - 20 56 cm

Cross-multiplying, we get (3x - 20)(72 cm) = (9 cm)(56 cm) = 504 cm²

Dividing both sides by 72 cm, we get:

3x - 20 = (504 cm²) / (72 cm) = 7

Then 3x - 20 = 7, and 3x = 27. Then x must be 9.

4 0

3 years ago

Read 2 more answers

Determine formula of the nth term 2, 6, 12 20 30,42

nalin [4]

Check the forward differences of the sequence.

If $\{a_n\} = \{2,6,12,20,30,42,\ldots\}$ , then let $\{b_n\}$ be the sequence of first-order differences of $\{a_n\}$ . That is, for n ≥ 1,

$b_n = a_{n+1} - a_n$

so that $\{b_n\} = \{4, 6, 8, 10, 12, \ldots\}$ .

Let $\{c_n\}$ be the sequence of differences of $\{b_n\}$ ,

$c_n = b_{n+1} - b_n$

and we see that this is a constant sequence, $\{c_n\} = \{2, 2, 2, 2, \ldots\}$ . In other words, $\{b_n\}$ is an arithmetic sequence with common difference between terms of 2. That is,

$2 = b_{n+1} - b_n \implies b_{n+1} = b_n + 2$

and we can solve for $b_n$ in terms of $b_1=4$ :

$b_{n+1} = b_n + 2$

$b_{n+1} = (b_{n-1}+2) + 2 = b_{n-1} + 2\times2$

$b_{n+1} = (b_{n-2}+2) + 2\times2 = b_{n-2} + 3\times2$

and so on down to

$b_{n+1} = b_1 + 2n \implies b_{n+1} = 2n + 4 \implies b_n = 2(n-1)+4 = 2(n + 1)$

We solve for $a_n$ in the same way.

$2(n+1) = a_{n+1} - a_n \implies a_{n+1} = a_n + 2(n + 1)$

Then

$a_{n+1} = (a_{n-1} + 2n) + 2(n+1) \\ ~~~~~~~= a_{n-1} + 2 ((n+1) + n)$

$a_{n+1} = (a_{n-2} + 2(n-1)) + 2((n+1)+n) \\ ~~~~~~~ = a_{n-2} + 2 ((n+1) + n + (n-1))$

$a_{n+1} = (a_{n-3} + 2(n-2)) + 2((n+1)+n+(n-1)) \\ ~~~~~~~= a_{n-3} + 2 ((n+1) + n + (n-1) + (n-2))$

and so on down to

$a_{n+1} = a_1 + 2 \displaystyle \sum_{k=2}^{n+1} k = 2 + 2 \times \frac{n(n+3)}2$

$\implies a_{n+1} = n^2 + 3n + 2 \implies \boxed{a_n = n^2 + n}$

6 0

1 year ago

Which are solutions of the equation 4x2 - 7x = 3x + 24? Check all that apply.

riadik2000 [5.3K]

Answer:

all work is shown and pictured

4 0

2 years ago

I need these answers by 1:30

hodyreva [135]

Answer:

its 4

Step-by-step explanation:

because u divied

3 0

2 years ago