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2 years ago

11

Fifth roots of 243 cos 2π 3 + i sin 2π 3 (a) use the formula zk = n r cos θ + 2πk n + i sin θ + 2πk n to find the indicated root

s of the complex number. (enter your answers in trigonometric form. let 0 ≤ θ < 2π.)

1 answer:

navik [9.2K]2 years ago

8 0

The answers are in the pic.

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The yearbook club had a meeting. The meeting had 24 people, which is three-fourths if the club. How many people are in the club?

Contact [7]

Answer:

18

Step-by-step explanation:

24*3/4=18

3 0

3 years ago

An art museum has a pentagon-shaped room. When drawn to scale on a coordinate grid, the corners of the room are points (18,20):

AURORKA [14]

Answer:

$2\ gal$

Step-by-step explanation:

we know that

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

we have

$A(18,20),B(4,20),C(4,4),D(16.2),E(22.10)$

step 1

Find the distance AB

we have

$A(18,20),B(4,20)$

substitute in the formula

$d=\sqrt{(20-20)^{2}+(4-18)^{2}}$

$d=\sqrt{(0)^{2}+(-14)^{2}}$

$AB=14\ ft$

step 2

Find the distance BC

we have

$B(4,20),C(4,4)$

substitute in the formula

$d=\sqrt{(4-20)^{2}+(4-4)^{2}}$

$d=\sqrt{(-16)^{2}+(0)^{2}}$

$BC=16\ ft$

step 3

Find the distance DE

we have

$D(16.2),E(22.10)$

substitute in the formula

$d=\sqrt{(10-2)^{2}+(22-16)^{2}}$

$d=\sqrt{(8)^{2}+(6)^{2}}$

$d=\sqrt{100}$

$DE=10\ ft$

step 4

Find the distance AE

we have

$A(18,20),E(22.10)$

substitute in the formula

$d=\sqrt{(10-20)^{2}+(22-18)^{2}}$

$d=\sqrt{(-10)^{2}+(4)^{2}}$

$d=\sqrt{116}$

$AE=10.77\ ft$

step 5

Find out the area of the four walls

To determine the area sum the length sides and multiply by the height of the walls

so

$A=(AB+BC+DE+AE)h$

substitute the given values

The height of the walls is 10 ft

$A=(14+16+10+10.77)10$

$A=(50.77)10$

$A=507.7\ ft^2$

step 6

Determine the number of gallons needed to paint the four walls

we know that

one gallon of paint is enough to cover 400 square feet

using proportion

$\frac{1}{400}\ \frac{gal}{ft^2}=\frac{x}{507.7}\ \frac{gal}{ft^2}\\\\x=507.7/400\\\\x= 1.27\ gal$

Round up

$x=2\ gal$

5 0

3 years ago

A collection of stamps consists of 3c stamps 5c stamps and 7c stamps. There are 6 more 3c stamps than 5c stamps and two more 7c

Deffense [45]

The number of 3¢ stamps that are in the collection is: 22.

<h3>What is an expression?</h3>

An expression can be defined as a mathematical equation which is used to show the relationship existing between two or more variables and numerical quantities.

In this exercise, you're required to determine the number of 3 cents (3¢) . Therefore, we would translate the word problem into an algebraic expression and then evaluate it as follows:

<u>Note:</u> 100 cents (¢) is equal to 1 dollar ($).

A collection of stamps consists of 3¢ stamps, 5¢ stamps and 7¢ stamps; 3¢ + 5¢ + 7¢ = 194

6 more 3¢ stamps than 5¢ stamps; 3¢ = 5¢ + 6 ⇒ 5¢ = 3¢ - 6

Two more 7¢ stamps than 3¢ stamps; 7¢ = 3¢ + 2

Combining the above equations, we have:

3¢ + 3¢ - 6 + 3¢ + 2 = 194

9¢ = 198

¢ = 198/9

¢ = 22.

Read more on expressions here: brainly.com/question/17361494

#SPJ1

<u>Complete Question:</u>

A collection of stamps consists of 3¢ stamps 5¢ stamps and 7¢ stamps. There are 6 more 3¢ stamps than 5¢ stamps and two more 7¢ stamps than 3¢ stamps. The total value of the stamps is $1.94. How many 3¢ stamps are in the collection?

6 0

1 year ago

The distribution of the amount of money in savings accounts for Florida State students has an average of 1,200 dollars and a sta

Anestetic [448]

Answer:

By the Central Limit Theorem, the sampling distribution of the sample mean amount of money in a savings account is approximately normal with mean of 1,200 dollars and standard deviation of 284.6 dollars.

Step-by-step explanation:

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Average of 1,200 dollars and a standard deviation of 900 dollars.

This means that $\mu = 1200, \sigma = 900$

Sample of 10.

This means that $n = 10, s = \frac{900}{\sqrt{10}} = 284.6$

The sampling distribution of the sample mean amount of money in a savings account is

By the Central Limit Theorem, approximately normal with mean of 1,200 dollars and standard deviation of 284.6 dollars.

7 0

3 years ago

For what value of k does the equation 6(x + 1) + 2 = 3(k5x + 1) + 3 have no solution?

NARA [144]

Answer:

k = (6/15)

Step-by-step explanation:

The equation is:

6*(x + 1) + 2 = 3*(k*5*x + 1) + 3

To have no solutions, we need to have something like:

x + 7 = x + 4

where we can remove x in both sides and end with

7 = 4

So this equation is false, meaning that there is no value of x such that this equation is true, then the equation has no solutions.

First, let's try to simplify our equation:

6*(x + 1) + 2 = 3*(k*5*x + 1) + 3

6*x + 6 + 2 = 3*k*5*x + 3*1 + 3

6*x + 8 = 15*k*x + 6

if 15*k = 6, then the system clerly has no solution.

then:

k = 6/15

then we get:

6*x + 8 = (6/15)*15*x + 6

6*x + 8 = 6*x + 6

8 = 6

The system has no solutions.

8 0

2 years ago