Fifth roots of 243 cos 2π 3 + i sin 2π 3 (a) use the formula zk = n r cos θ + 2πk n + i sin θ + 2πk n to find the indicated root
s of the complex number. (enter your answers in trigonometric form. let 0 ≤ θ < 2π.)
1 answer:
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So we have the equation:
Then we need to multiply by 4 on both sides to get rid of the denominator on the left:
Then we subtract 9 on both sides to solve for z:
Therefore the answer is z = -0.6.