Let
N--------> <span>members of the club
we know that
($192/(N+2)=3.20
192=(N+2)*3.20
3.20*N+6.40=192
3.20*N=192-6.40
N=185.60/3.20
N=58
the answer is
58</span>
A) If you have 12 dogs and cats (I assume 12 in total) and divide those by two, you get six dogs and six cats. It has to be more dogs than cats, and the sum of those two has to be twelve. So to reach the sum 12, while one number is bigger that the other, the number has to be 7 or more.
Answer:
cosine i think tell me if im wrong
Step-by-step explanation:
Constant is occurring continuously over a period of time so C is the correct answer because C is constant for a period of time