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3 years ago

Simplify the expression: 7 - 7(5 + x) - 9x Your answer

Mathematics

1 answer:

Gekata [30.6K]3 years ago

5 0

Answer:

-16x-28

Step-by-step explanation:

Break it into little pieces; start with distributing the -7:

-7(5+x)

-35-7x

Now add the rest of the problem: 7-35-7x-9x

Combine like terms: 7-35 7x-9x

7-35=-28 7x-9x=-16x

Rearrange so the coefficient and variable are upfront, giving you:

-16x-28

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Answer:

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Step-by-step explanation:

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2 years ago

Two points A and B are A (0,1) and B (2,4). Write down the eqaution of the line perpendicular to AB and Passing through the poin

Zielflug [23.3K]

Answer:

y = -2x/3 + 2

Step-by-step explanation:

A(0,1), B(2,4)

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2 years ago

If 3x + 6 = 18, then x = ?

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Answer:

X=4

Step-by-step explanation:

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2 years ago

On a linear X temperature scale, water freezes at −115.0°X and boils at 325.0°X. On a linear Y temperature scale, water freezes

belka [17]

Answer:

The current temperature on the X scale is 1150 °X.

Step-by-step explanation:

Let is determine first the ratio of change in X linear temperature scale to change in Y linear temperature scale:

$r = \frac{\Delta T_{X}}{\Delta T_{Y}}$

$r = \frac{325\,^{\circ}X-(-115\,^{\circ}X)}{-25\,^{\circ}Y - (-65.00\,^{\circ}Y)}$

$r = 11\,\frac{^{\circ}X}{^{\circ}Y}$

The difference between current temperature in Y linear scale with respect to freezing point is:

$\Delta T_{Y} = 50\,^{\circ}Y - (-65\,^{\circ}Y)$

$\Delta T_{Y} = 115\,^{\circ}Y$

The change in X linear scale is:

$\Delta T_{X} = r\cdot \Delta T_{Y}$

$\Delta T_{X} = \left(11\,\frac{^{\circ}X}{^{\circ}Y} \right)\cdot (115\,^{\circ}Y)$

$\Delta T_{X} = 1265\,^{\circ}X$

Lastly, the current temperature on the X scale is:

$T_{X} = -115\,^{\circ}X + 1265\,^{\circ}X$

$T_{X} = 1150\,^{\circ}X$

The current temperature on the X scale is 1150 °X.

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2 years ago

What percent of 30 is 18

Marina CMI [18]

18 is 60 percent of 30. 3 percent is 10 percent of 30 so 3 x 6 equals 18.

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1 year ago

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