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3 years ago

Solve 3x + y = -5 -2x + 3y = 18 with the substitution method PLEASE HELPPPP

Mathematics

1 answer:

valina [46]3 years ago

5 0

Hey! Great to see you again.

Based on what we learned last time, we can apply it to this equation!

Solve 3x+y =−5 for y:

3x+y=−5

3x+y+−3x=−5+−3x Let us add -3x to both sides.

y=−3x−5.

Substitute −3x−5 for y in −2x+3y=18:

−2x+3y=18

−2x+3(−3x−5)=18

−11x−15=18 Simplify both sides :)

−11x−15+15=18+15 Add 15 to each side.

−11x=33

x = -3

Now solve for y.

−3 for x in y=−3x−5:

y=(−3)(−3)−5

Can you solve this equation? Let me know if you need help, tell me what you get! :) That will be your y answer. :D

Have a great one!

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2 years ago

Solve the triangle. Round your answers to the nearest tenth. A. m∠A=43, m∠B=55, a=16 B. m∠A=48, m∠B=50, a=23 C. m∠A=48, m∠B=50,

alexgriva [62]

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Step-by-step explanation:

Given:

∆ABC,

m<C = 82°

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Required:

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SOLUTION:

Find m<B using the law of sines:

$\frac{sin(B)}{b} = \frac{sin(C)}{c}$

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$sin(B)*29 = sin(82)*24$

$\frac{sin(B)*29}{29} = \frac{sin(82)*24}{29}$

$sin(B) = \frac{sin(82)*24}{29}$

$sin(B) = 0.8195$

$B = sin^{-1}(0.8195)$

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Find m<A:

m<A = 180 - (82 + 55) => sum of angles in a triangle.

= 180 - 137

m<A = 43°

Find a using the law of sines:

$\frac{a}{sin(A)} = \frac{b}{sin(B)}$

$\frac{a}{sin(43)43} = \frac{24}{sin(55)}$

Cross multiply

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