A^3
a to the power of three
The bases are both 2, so we would subtract the exponents. This is because the rule is
(a^b)/(a^c) = a^(b-c)
In this case,
a = 2
b = 3/4
c = 1/2
So this means
b - c = (3/4) - (1/2) = (3/4) - (2/4) = 1/4
After subtracting the exponents, the final exponent is 1/4
So the expression simplifies to 2^(1/4) which is the same as
![\sqrt[4]{2}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B2%7D)
(fourth root of 2)
Answer:
Step-by-step explanation:
The Fundamental Theorem of Algebra states that the number of complex roots a polyomial has is equal to its highest exponent. This is a squared polynomial; second degree; quadratic. When it is factored, no matter what types of numbers you get as the solution, you will ALWAYS have 2 of them. When this quadratic is factored, we get that x = 3 and x = 3. That means that this is a quadratic that touches the x-axis at (3, 0). It doesn't go through, it only touches. We do have 2 roots, but since they're the same, we say we have a multiplicity 2 of that root. The closest you'll come to that in your choices is A. Apparently your text refers to multiplicity 2 as a double root.
Answer:
1500÷30=50
40× 50=2000
2000-1500=500.
therefore the answer is500
They should divided by 1 for the last step