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yaroslaw [1]
3 years ago
7

What is the distance between the following points?

Mathematics
1 answer:
likoan [24]3 years ago
7 0

Answer:

11.

Step-by-step explanation:

9 right, and 2 up

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ioda

-12 = 6 + 2/3y

Subtract 6 from both sides

-18 = 2/3y

Multiply both sides by 3

-54 = 2y

Divide both sides by 2

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Help please please please please please<br> 6th &amp; 7th
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The first variable that I solved for was "a" and a=e^\frac{in(b)}{2}[tex]{[tex]  0}

The same is also true for "b", but when you put both "a" and "b" together the only combination that I have found to work is a=\frac{1}{2} , b=\frac{1}{4}

Next you plug these numbers in for "a" and "b" on the second equation to get something that looks like this: log_\frac{1}{2}_*_\frac{1}{4} (\frac{\sqrt{\frac{1}{2}}}{\sqrt[3]{\frac{1}{4}}}  )= -\frac{1}{18} and the picture below shows where the answer becomes a negative fraction.

https://www.symbolab.com/solver/logarithms-calculator/%20%5Clog_%7B%5Cfrac%7B1%7D%7B2%7D%5Ccdot%5Cfrac%7B1%7D%7B4%7D%7D%5Cleft(%5Cfrac%7B%5Csqrt%7B%5Cfrac%7B1%7D%7B2%7D%7D%7D%7B%5Csqrt%5B3%5D%7B%5Cfrac%7B1%7D%7B4%7D%7D%7D%5Cright)

If you paste that link in your search bar it will give you a even more in depth understanding of how to get this answer

Next is #7, the easier of the two.There are two ways to solve for your answers. According to the graph of this equation there are four possible real solutions. x=2,-2,\sqrt{2}, and -\sqrt{2} . (This does not account for any complex solutions)

Notice that the bases are conjugates which is why the answers are so "nice"

The key is in the exponents

if x^{2} -3 =1 then the sum on the conjugates will be 10 so

x^{2}-3=1
x^{2}=4
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Now for the other two

the solution is also true if x^{2}-3=-1

so

x^{2}-3 = -1\\x^{2}=2\\x=\left \{ {{\sqrt{2}} \atop {-\sqrt{2}}} \right.

the four real solutions are 2, -2, \sqrt{2} ,-\sqrt{2}



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