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o-na [289]
3 years ago
14

Abel throws a dart that hits the square shown. What is the probability that the dart does NOT hit a point in the circle?

Mathematics
1 answer:
iragen [17]3 years ago
7 0

A square side is twice of the radius

sq side: 4 x 2

sq side: 8

find the area of the square.

A = b x h

A = (8) x (8)

A = 64

<em>Area of square is 64</em>

----------------------------------------------------------------------------------------------------------------

Find the area of the circle

Area of circle:

A = πr²

A = π(4)²

A = 16π

A = 16(3.14)

A = 50.24

----------------------------------------------------------------------------------------------------------------

Divide the circle from the total

50.24/64

50.24/64 = 0.785

0.785 = 78.5/100 = 78.5%

----------------------------------------------------------------------------------------------------------------

Subtract the circle's percentage from 100% (the total)

100 - 78.5 = 21.5

21.5% is your chance of not hitting a point in the circle.

-----------------------------------------------------------------------------------------------------------------

21.5%, or (B), is your answer

-----------------------------------------------------------------------------------------------------------------

hope this helps

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Answer:

(a)  As time increases, the amount of water in the pool increases.

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(b)  65 gallons

Step-by-step explanation:

From inspection of the table, we can see that <u>as time increases, the amount of water in the pool increases</u>.

We are told that Ann adds water at a constant rate.  Therefore, this can be modeled as a linear function.  

The rate at which the water is increasing is the <em>rate of change</em> (which is also the <em>slope </em>of a linear function).

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\textsf{let}\:(x_1,y_1)=(8, 153)

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Input these into the slope formula:

\textsf{slope}\:(m)=\dfrac{y_2-y_1}{x_2-x_1}=\dfrac{197-153}{12-8}=\dfrac{44}{4}=11

Therefore, the rate at which the water in the pool is increasing is:

<u>11 gallons per minute</u>

To find the amount of water that was already in the pool when Ann started adding water, we need to create a linear equation using the found slope and one of the ordered pairs with the point-slope formula:

y-y_1=m(x-x_1)

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\implies y-153=11x-88

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When Ann had added no water, x = 0.  Therefore,

y=11(0)+65

y=65

So there was <u>65 gallons</u> of water in the pool before Ann starting adding water.

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