All categories

3 years ago

Evaluate ab+c for a=2 b=3 and c=4 A 9 B10 C27

Mathematics

2 answers:

dezoksy [38]3 years ago

7 0

Ab+c

2(3)+4
6+4
Your answer is B 10

Phoenix [80]3 years ago

5 0

Hey there!

<h3>ab + 2 </h3><h3>If a = 2, b =3 . and c = 4 </h3><h3>Your problem would change </h3><h3>2(3) + 4 </h3><h2>2(3) = 6 </h2><h2>6 + 4 = 10 </h2><h2>Answer when we "evaluate" is 10 </h2><h2>Good luck on your assignment and enjoy your day!</h2>

~ $LoveYourselfFirst:)$

You might be interested in

What is the square root of 121

Dvinal [7]

Answer:

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Which pair of funtions is not a pair of inverse functions? please help!!

antiseptic1488 [7]

Answer:

$f(x)=\frac{x}{x+20} , g(x)=\frac{20x}{x-1}$

Step-by-step explanation:

we know that

To find the inverse of a function, exchange variables x for y and y for x. Then clear the y-variable to get the inverse function.

we will proceed to verify each case to determine the solution of the problem

<u>case A)</u> $f(x)=\frac{x+1}{6} , g(x)=6x-1$

Find the inverse of f(x)

Let

y=f(x)

Exchange variables x for y and y for x

$x=\frac{y+1}{6}$

Isolate the variable y

$6x=y+1$

$y=6x-1$

Let

$f^{-1}(x)=y$

$f^{-1}(x)=6x-1$

therefore

f(x) and g(x) are inverse functions

<u>case B)</u> $f(x)=\frac{x-4}{19} , g(x)=19x+4$

Find the inverse of f(x)

Let

y=f(x)

Exchange variables x for y and y for x

$x=\frac{y-4}{19}$

Isolate the variable y

$19x=y-4$

$y=19x+4$

Let

$f^{-1}(x)=y$

$f^{-1}(x)=19x+4$

therefore

f(x) and g(x) are inverse functions

<u>case C)</u> $f(x)=x^{5}, g(x)=\sqrt[5]{x}$

Find the inverse of f(x)

Let

y=f(x)

Exchange variables x for y and y for x

$x=y^{5}$

Isolate the variable y

fifth root both members

$y=\sqrt[5]{x}$

Let

$f^{-1}(x)=y$

$f^{-1}(x)=\sqrt[5]{x}$

therefore

f(x) and g(x) are inverse functions

<u>case D)</u> $f(x)=\frac{x}{x+20} , g(x)=\frac{20x}{x-1}$

Find the inverse of f(x)

Let

y=f(x)

Exchange variables x for y and y for x

$x=\frac{y}{y+20}$

Isolate the variable y

$x(y+20)=y$

$xy+20x=y$

$y-xy=20x$

$y(1-x)=20x$

$y=20x/(1-x)$

Let

$f^{-1}(x)=y$

$f^{-1}(x)=20x/(1-x)$

$\frac{20x}{1-x}\neq \frac{20x}{x-1}$

therefore

f(x) and g(x) is not a pair of inverse functions

7 0

3 years ago

Read 2 more answers

What's the answer???

sertanlavr [38]

The answer is Letter "D"

4 0

3 years ago

How many solutions does this system

mr Goodwill [35]

The answer is B.) one

Hope this helps :)

5 0

3 years ago

Please help 30 points and if I get correct answer i will brainiest them

WINSTONCH [101]

Answer:

9,-4

Step-by-step explanation:

-9×4=-36

Negative × Positive = Negative

8 0

3 years ago