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OverLord2011 [107]
3 years ago
14

Evaluate ab+c for a=2 b=3 and c=4 A 9 B10 C27

Mathematics
2 answers:
dezoksy [38]3 years ago
7 0
Ab+c

2(3)+4
6+4
Your answer is B 10
Phoenix [80]3 years ago
5 0

Hey there!

<h3>ab + 2 </h3><h3>If a = 2, b =3 . and c = 4 </h3><h3>Your problem would change </h3><h3>2(3) + 4 </h3><h2>2(3) = 6 </h2><h2>6 + 4 = 10 </h2><h2>Answer when we "evaluate" is 10 </h2><h2>Good luck on your assignment and enjoy your day!</h2>

~LoveYourselfFirst:)

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What is the square root of 121
Dvinal [7]

Answer:

11

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Which pair of funtions is not a pair of inverse functions? please help!!
antiseptic1488 [7]

Answer:

f(x)=\frac{x}{x+20} , g(x)=\frac{20x}{x-1}

Step-by-step explanation:

we know that

To find the inverse of a function, exchange variables x for y and y for x. Then clear the y-variable to get the inverse function.

we will proceed to verify each case to determine the solution of the problem

<u>case A)</u> f(x)=\frac{x+1}{6} , g(x)=6x-1

Find the inverse of f(x)

Let

y=f(x)

Exchange variables x for y and y for x

x=\frac{y+1}{6}

Isolate the variable y

6x=y+1

y=6x-1

Let

f^{-1}(x)=y

f^{-1}(x)=6x-1

therefore

f(x) and g(x) are inverse functions

<u>case B)</u> f(x)=\frac{x-4}{19} , g(x)=19x+4

Find the inverse of f(x)

Let

y=f(x)

Exchange variables x for y and y for x

x=\frac{y-4}{19}

Isolate the variable y

19x=y-4

y=19x+4

Let

f^{-1}(x)=y

f^{-1}(x)=19x+4

therefore

f(x) and g(x) are inverse functions

<u>case C)</u> f(x)=x^{5}, g(x)=\sqrt[5]{x}

Find the inverse of f(x)

Let

y=f(x)

Exchange variables x for y and y for x

x=y^{5}

Isolate the variable y

fifth root both members

y=\sqrt[5]{x}

Let

f^{-1}(x)=y

f^{-1}(x)=\sqrt[5]{x}

therefore

f(x) and g(x) are inverse functions

<u>case D)</u> f(x)=\frac{x}{x+20} , g(x)=\frac{20x}{x-1}

Find the inverse of f(x)

Let

y=f(x)

Exchange variables x for y and y for x

x=\frac{y}{y+20}

Isolate the variable y

x(y+20)=y

xy+20x=y

y-xy=20x

y(1-x)=20x

y=20x/(1-x)

Let

f^{-1}(x)=y

f^{-1}(x)=20x/(1-x)

\frac{20x}{1-x}\neq \frac{20x}{x-1}

therefore

f(x) and g(x) is not a pair of inverse functions

7 0
3 years ago
Read 2 more answers
What's the answer???
sertanlavr [38]
The answer is Letter "D"
4 0
3 years ago
How many solutions does this system
mr Goodwill [35]
The answer is B.) one




Hope this helps :)
5 0
3 years ago
Please help 30 points and if I get correct answer i will brainiest them
WINSTONCH [101]

Answer:

9,-4

Step-by-step explanation:

-9×4=-36

Negative × Positive = Negative

8 0
3 years ago
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