To answer this question you have to create a system of equations. The first equation will be that Devi's money (x) equals her brother's money (y), or x = y. The next equation would be that (3/5)x + (7/10)y = 78. You than can substitute x in for y because x = y. The equation would know be (3/5)x + (7/10)x = 78. You then combine the like terms to create an equation of (13/10)x = 78. Then, multiply both sides by 10 / 13 in order to isolate x. This will create the equation x = 60. This means that Devi and her brother each had 60 dollars. You then find out how much they spent and add it together. You can do so with the equation (2/5)x + (3/10)y = z, with z being total money spent. You substitute 60 in for x and for y then solve. When you solve you see that 24 + 18 = z, or that z equals 42. In other words, they spent 42 dollars altogether.
First, let's simplify each expression by combining like terms:
A: 9x-3x-4 = 6x-4
B: 12x-4 = 12x-4 (Already Combined terms)
C: 5x+x-4 = 6x-4
When looking at the list of equations, it is clear that only Expression A and C are equivalent. Brianna failed to combine like terms and plug in more points than 0.
I Hope this Helps!
-Sinnamin
Answer:
64,890
Step-by-step explanation:
105×3 =315
103×2= 206
315×206= 64,890
Answer:
D. f(x) is shifted up 1 unit to g(x).
Step-by-step explanation:
Just let's look at the y-intercept of each function.
f(0) = 0
g(0) = 1
Also remember that a vertical shift of N units is written as:
g(x) = f(x) + N
where if N is positive, the shift is upwards, and if N is negative, the shift is downwards.
then we can write, for the particular value x = 0
g(0) = f(0) + N
replacing the values
1 = 0 + N
1 = N
Then N is positive, so we have a shift up of one unit.
The correct option is:
D. f(x) is shifted up 1 unit to g(x).
440 gallons of 80 % antifreeze solution must be mixed with 80 gallons of 15% antifreeze to get a mixture that is 70% antifreeze
<em><u>Solution:</u></em>
Let "x" be the gallons of 80 % antifreeze added
Therefore, "x" gallons of 80 % antifreeze solution must be mixed with 80 gallons of 15% antifreeze
Final mixture is x + 80
Therefore, we can frame a equation as:
"x" gallons of 80 % antifreeze solution must be mixed with 80 gallons of 15% antifreeze to get (x + 80) gallons of 70 % antifreeze
Thus, we get,
x gallons of 80 % + 80 gallons of 15 % = (x + 80) gallons of 70 %
Thus 440 gallons of 80 % antifreeze solution must be mixed
