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3 years ago

Select the factored form of the polynomial that is modeled by this geometric diagram.

1 answer:

4 0

The diagram is not given. I will however write out each polynomial, so that you can select whichever corresponds to your question.

Step-by-step explanation:

(2x + 8)(4x + 8)

= 8x² + 16x + 24x + 64

= 8x² + 40x + 64

= 8(x² + 5x + 8)

(x + 2)(x+4)

= x² + 4x + 2x + 8

= x² + 6x + 8

(x + 1)(x+8)

= x² + 8x + x + 8

= x² + 9x + 8

* (*+ 4x)(2x + 3) NOT CLEAR

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Solve for xif mZRQS = 2x+4 and mZTQS = 6x+ 20.<br> 180<br> 19.5<br> -4<br> 90

Likurg_2 [28]

Answer:

x= -4

Step-by-step explanation:

2x+4=6x+20

so 2x-6x=20-4

divide both sides by -4

-4x/-4 = 16/4

=-4

7 0

2 years ago

Which of the equations below could be the equation of this parabola?

nirvana33 [79]

Answer:

$y=-4x^2$ is the equation of this parabola.

Step-by-step explanation:

Let us consider the equation

$y=-4x^2$

$\mathrm{Domain\:of\:}\:-4x^2\::\quad \begin{bmatrix}\mathrm{Solution:}\:&\:-\infty \:$

$\mathrm{Range\:of\:}-4x^2:\quad \begin{bmatrix}\mathrm{Solution:}\:&\:f\left(x\right)\le \:0\:\\ \:\mathrm{Interval\:Notation:}&\:(-\infty \:,\:0]\end{bmatrix}$

$\mathrm{Axis\:interception\:points\:of}\:-4x^2:\quad \mathrm{X\:Intercepts}:\:\left(0,\:0\right),\:\mathrm{Y\:Intercepts}:\:\left(0,\:0\right)$

$\mathrm{The\:vertex\:of\:an\:up-down\:facing\:parabola\:of\:the\:form}\:y=a\left(x-m\right)\left(x-n\right)$

$\mathrm{is\:the\:average\:of\:the\:zeros}\:x_v=\frac{m+n}{2}$

$y=-4x^2$

$\mathrm{The\:parabola\:params\:are:}$

$a=-4,\:m=0,\:n=0$

$x_v=\frac{m+n}{2}$

$x_v=\frac{0+0}{2}$

$x_v=0$

$\mathrm{Plug\:in}\:\:x_v=0\:\mathrm{to\:find\:the}\:y_v\:\mathrm{value}$

$y_v=-4\cdot \:0^2$

$y_v=0$

Therefore, the parabola vertex is

$\left(0,\:0\right)$

$\mathrm{If}\:a$

$\mathrm{If}\:a>0,\:\mathrm{then\:the\:vertex\:is\:a\:minimum\:value}$

$a=-4$

$\mathrm{Maximum}\space\left(0,\:0\right)$

so,

$\mathrm{Vertex\:of}\:-4x^2:\quad \mathrm{Maximum}\space\left(0,\:0\right)$

Therefore, $y=-4x^2$ is the equation of this parabola. The graph is also attached.

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3 years ago

If P(x)=x^2-1 and q(x)=5(x-1), which expression is equivalent to (p-q)(x)

zheka24 [161]

Okay so you do p(x) -q(x) and you get (x)^2-5x hope this helps. (Also hope that trigonometry I'm taking comes through lol)

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3 years ago

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sleet_krkn [62]

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hoa [83]

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3 years ago