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luda_lava [24]
3 years ago
14

If a ÷ b = 2 and b ÷ c =3/4, what is the value of c ÷ a? Express your answer as a common fraction.

Mathematics
2 answers:
liberstina [14]3 years ago
8 0

Answer:

a/b = 2

so , a = 2b

b/c = 3/4

so , c = 4b/3

c/a = (4b/3) / 2b

which gives 2/3

Step-by-step explanation:

rewona [7]3 years ago
5 0

Step-by-step explanation:

\frac{b}{c}  =  \frac{3}{4}  \\  3c = 4b \\ c =  \frac{4b}{3}

\frac{a}{c}  = 2 \\ a = 2b

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a box with a square base is taller than it is wide. in order to send the box through the US mail, the height of the box and the
NemiM [27]

The given box has the shape of a <u>cuboid</u>, since its <em>height</em> is greater than its <em>width</em>. Thus, the <em>maximum volume</em> for such box is 11200 in^{3}.

The <u>volume</u> of an object is a measure of it <em>containing</em> capacity. Since the given box has a taller <em>height</em> than its <em>width</em>, then it has the shape of a <em>cuboid</em>. The<u> volume</u> of a cuboid is given as:

volume = length x width x height

            = area x height

Given that the <u>sum</u> of the <em>perimeter</em> of its base and its <em>height</em> is not more than 108 inches, we can say; let the sides of the <em>square</em> base be represented by l and its height by h.

Then;

4l + h = 108

Therefore, maximum volume for the box can be attained when l = 20 inches and h = 28 inches.

So that;

4(20) + 28 = 80 + 28

                 = 108 inches

Thus;

maximum volume = area of the square base x height

                        = 400 x 28

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The <u>maximum</u> <u>volume</u> for such a box would be 11200 in^{3}.

Visit: brainly.com/question/20463446

5 0
2 years ago
(1 point) A rectangular storage container with an open top is to have a volume of 12 cubic meters. The length of its base is twi
Vlada [557]

Answer:

The cost of the materials for the cheapest such container is approximately $249.8

Step-by-step explanation:

The volume the rectangular container is to have = 12 m³

The base length = 2 × The width of the base

The cost of the material for the base = 11 dollars/m²

The cost of the other sides = 9 dollars/m²

Let 'l', 'w', and 'h' represent the length and width of the base and the height of the rectangular storage container respectively, we have;

l = 2·w

l × w × h = 12 m³

∴ h = 12/(l × w) = 12/(2·w × w) = 6/w²

The cost of the open top rectangular container = The cost of the base + The cost of the 4 sides

The cost of the base = The area of the base × $11/m²

∴ The cost of the base = l × w × 11 =2·w × w × 11 = 22·w²

The cost of the 4 sides = The area of the four sides × $9/m²

∴ The cost of the 4 sides = 2 × (l × h + w × h) × 9

The cost of the 4 sides = 2 × (2·w × 6/w² + w × 6/w²) × 9 = 18 × (12/w + 6/w) = 324/w

∴ The cost of the open top rectangular container = 22·w² + 324/w

The coefficient of w² in the equation of the cost is positive, therefore, the cost of the materials for the cheapest such container, 'C', is given by value of 'w' at the minimum point of the equation, 22·w² + 324/w, which is given by the equating the derivative of the equation to zero as follows;

d(22·w² + 324/w)/dw = 0

∴ 44·w - 324/w² = 0

∴ 44·w = 324/w²

w³ = 324/44 = 81/11

w = ∛(81/11)

∴ C = 22·w² + 324/w = 22 × (∛(81/11))² + 324/(∛(81/11)) = 486/(∛(81/11)) ≈ 249.8

The cost of the materials for the cheapest such container, C ≈ $249.8

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djverab [1.8K]

Complement of an angle = 90° - x.

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= 90 + x - 90 + x

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It is given that supplement of the complement of an angle less the complement of an angle exceeds the quotient of the supplement of the angle and the number 3 by 73.

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Multiply both sides by 3.

6x = 180 - x + 219

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Add x to both sides.

6x + x = 399

7x = 399

Divide both sides by 7.

x = 57

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Answer:

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