Find the vertex of h(x)=(x+6)^2

1 answer:

6 0

Convert it into the y=a(x-h)+k form and the values of h and k are your vertex.
You can convert by completing the square method.

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Find the x and y intercepts 5y + 3x = 15

Tomtit [17]

First, find the x-intercept.

The x-intercept will be at the point (x, 0) where x is any real number. If we substitute the x-coordinate and the y-coordinate for the x and y variables in the equation, we can solve for x.

5y + 3x = 15
5(0) + 3x = 15
3x + 15
x = 5

We found the x-intercept now find the y-intercept with the same process.

The y-intercept will be at the point (0, y) where y is any real number.

5y + 3x = 15
5y + 3(0) = 15
5y = 15
y = 3

So, the x-intercept is (5, 0) and the y-intercept is (0, 3)

8 0

3 years ago

Instructions are in the picture

Phantasy [73]

Answer:

123123 3213123 12312 dasdsd aw dasd sda asdasd

Step-by-step explanation:

3 0

3 years ago

If A is the subset of B, then A intersects B =B or A is a union B = B

vaieri [72.5K]

Answer: A union B = B

The first one should’ve said A intersects B = A because the entirety of A exists in B

7 0

3 years ago

What is the square root of 49 multiplied by the square root of 9

fiasKO [112]

First we need to find the the answer to both the square root of 49 and 9.

The "square root" is a term referring to a number, multiplied by itself (x • x) would be = to your square root.

So for example: Square root of 16 = 4 because 4*4=16

So lets get out numbers:

$\sqrt{9} =3
$
$\sqrt{49}=7$

Now you multiply 3*7 (or 7*3) and you get 21.

Final answer: 21

7 0

3 years ago

Read 2 more answers

2) 4 6 2 3 If L= | 5 8 and M= 1 4 3 -2 -5 3 3 Find L-M -)) 2 4 8 A ) 3 4 5 2 3 B) 4 4 8 -5 6 9 o 6 12 -2 1 6 6 2 D) 9 12 1

Misha Larkins [42]

$\\ \sf\longmapsto L-M$

Put values

$\sf \left[\begin{array}{cc}\sf 4&\sf 6\\ \sf 5 &\sf 8 \\ \sf 3 &\sf -2\end{array}\right]-\left[\begin{array}{cc}\sf 2&\sf 3\\ \sf 1 &\sf 4 \\ \sf -5&\sf3\end{array}\right]$

Just substract corresponding terms

$\\ \sf\longmapsto \left[\begin{array}{cc}\sf 2 &\sf 3\\ \sf 4&\sf4\\ \sf 8&\sf -5\end{array}\right]$

Option B

6 0

3 years ago