Answer:
4
Step-by-step explanation:
How many selfies did Tania take? (my first answer would be too many, but that's probably not the answer you're looking for :-) )
We know that each cousin appear 2 or 3 times overall.
If she would have taken each cousin exactly 2 times, that would be 16 cousins/photos
If she would have taken each cousin exactly 3 times, that would be 24 cousins/photos
We know there's exactly 5 cousins per photo...
so we have to find a multiple of 5 cousins/photos that is between 16 and 24.
The only possibility is 20 cousins/photos. 20 / 5 = 4 photos.
The value of the expression 4(5² - 3 - 2x)² is <u>576</u>.
In the question, we are asked to evaluate the expression 4(5² - 3 - 2x)², where x = 5.
To find the value of the expression, we find the value of each term with the value assigned to the variable and then put back the terms in the expression to get the final value.
The term 5² = 25.
The term 2x, when x = 5, can be shown as 2x = 2*5 = 10.
Taking the terms back to the expression, we get:
4(5² - 3 - 2x)²
= 4(25 - 3 - 10)²
= 4(12)²
= 4(144)
= 576.
Thus, the value of the expression 4(5² - 3 - 2x)² is <u>576</u>.
Learn more about solving expressions at
brainly.com/question/723406
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Answer:
super simple its blueprints!
Step-by-step explanation:
The question is incomplete, here is the complete question:
The half-life of a certain radioactive substance is 46 days. There are 12.6 g present initially.
When will there be less than 1 g remaining?
<u>Answer:</u> The time required for a radioactive substance to remain less than 1 gram is 168.27 days.
<u>Step-by-step explanation:</u>
All radioactive decay processes follow first order reaction.
To calculate the rate constant by given half life of the reaction, we use the equation:
where,
= half life period of the reaction = 46 days
k = rate constant = ?
Putting values in above equation, we get:
The formula used to calculate the time period for a first order reaction follows:
where,
k = rate constant = 
t = time period = ? days
a = initial concentration of the reactant = 12.6 g
a - x = concentration of reactant left after time 't' = 1 g
Putting values in above equation, we get:
Hence, the time required for a radioactive substance to remain less than 1 gram is 168.27 days.
Answer:
We will take option B.
Step-by-step explanation:
Option A) |4 − 1| = 3 units
Option B) |4 − (−1)| = 5 units
Option C) |−4 + (−1)| = 5 units
Option D) |−4 − (−1)| = 3 units.
Now, from the number line and from the points given on the number line it is clear that the distance from one point to another is 5 units.
So. option B or Option C can be the right one.
Now, the right side point is on +4 point and the left side point is on -1 point.
So, the distance between those points will be calculated as 4 - (- 1) = 5.
Therefore, we will take option B. (Answer)
