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hodyreva [135]
3 years ago
9

Sarah, Dan & Gavyn share some

Mathematics
1 answer:
gregori [183]3 years ago
5 0

Answer:

$11.25

Step-by-step explanation:

45/4=11.25

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They can be 25hours and 10 minutes apart. <span>This is possible because the </span>International dateline is not a straight line<span>.
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3 years ago
Which expression is equivalent to the one below?
Alex17521 [72]

Answer:

D . 9 .1/13

Step-by-step explanation:

9\div 13 = \frac{9}{13} \\\\9\cdot \frac{1}{13}\\\\=\frac{9}{1}\cdot \frac{1}{13}\\\\=\frac{9\cdot \:1}{1\cdot \:13}\\\\=\frac{9}{13}

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3 years ago
Please help. Answer only if u can show your work or explain
Elenna [48]
Gropu like terms
(-1/2)x+(3/2)x-4x+3+5=
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3 0
3 years ago
Read 2 more answers
On ITV's Homework Hotline, it's time for "Rudolf's Rules." If you guess what rule Rudolf is using you get a prize. Someone puts
oee [108]

Answer:

y = 3x -18 ( where y =  balls sent back by Rudolf; x= balls  given to Rudolf)

Step-by-step explanation:

x (Balls given)       y( Balls sent back)

8                             6                    Δy/Δx  = (27-6)/(15-8) =  3

15                            27

25                           57                 Δy/Δx  = (57-27)/(25-15) =  3

Observing the number sequence shows constant gradient and as such we can use equation of a straight line to relate the two variables.

Using the equation of a straight line we have:

(y-y1)/(x-x1) =  (y2-y1)/(x2-x1)

y-6/x-8  =       (27-6)/(15-8)

y-6/x-8  =    3

y-6        =  3(x-8)

y-6  = 3x - 24

y = 3x-18

7 0
3 years ago
Graph triangle RST with vertices R(3, 7), S(-5, -2), and T(3, -5) and its image after a reflection over x = -3.​
kirill115 [55]

Given:

The vertices of a triangle are R(3, 7), S(-5, -2), and T(3, -5).

To find:

The vertices of the triangle after a reflection over x = -3 and plot the triangle and its image on the graph.

Solution:

If a figure reflected across the line x=a, then

(x,y)\to (-(x-a)+a,y)

(x,y)\to (-x+a+a,y)

(x,y)\to (2a-x,y)

The triangle after a reflection over x = -3. So, the rule of reflection is

(x,y)\to (2(-3)-x,y)

(x,y)\to (-6-x,y)

The vertices of triangle after reflection are

R(3,7)\to R'(-6-3,7)

R(3,7)\to R'(-9,7)

Similarly,

S(-5,-2)\to S'(-6-(-5),-2)

S(-5,-2)\to S'(-6+5,-2)

S(-5,-2)\to S'(-1,-2)

And,

T(3,-5)\to T'(-6-3,-5)

T(3,-5)\to T'(-9,-5)

Therefore, the vertices of triangle after reflection over x=-3 are R'(-9,7), S'(-1,-2) and T'(-3,-5).

3 0
3 years ago
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