All categories

3 years ago

What type of energy increases when friction does work on an object

1 answer:

4 0

Kinetic friction, for example, generally turns energy into heat, and although we associate kinetic friction with energy loss, it really is just a way of transforming kinetic energy into thermal energy. The law of conservation of energy applies always, everywhere, in any situation. ?

You might be interested in

How did harlow shapley conclude that the sun was not in the center of the milky way galaxy?

timurjin [86]

We learned that We are in the disk of the Galaxy, about 5/8 of the way from the center.

<h3>What is the work of Harlow Shapley?</h3>

Shapley, who was headquartered in Boulder, Colorado, used Cepheid variable stars to estimate the size of the Milky Way Galaxy and its position relative to the Sun. In 1953, he published his "liquid water belt" theory, today known as the concept of a livable zone.

There are many stars, grains of dust, and gas in the Milky Way. It is known as a spiral galaxy because, from the top or bottom, it would appear to be whirling like a pinwheel. About 25,000 light-years from the galaxy's nucleus, the Sun is situated on one of the spiral arms.

Approximately 5/8 of the way from the galaxy's nucleus, we are in the disc. William Herschel believed that the Sun and Earth were about in the middle of the vast cluster of stars known as the Milky Way.

To learn more about Harlow Shapley's original estimate go to - brainly.com/question/28145909

#SPJ4

3 0

2 years ago

How does the wind turbine generator work?

AnnZ [28]

Answer: wind pushes directly against the blades of the turbine, which converts the linear motion of the wind into the rotary motion, then it spins the generator's rotor and the harder the wind pushes, the more electrical energy can be generated.

Explanation:

5 0

3 years ago

How can damage to living things occur from exposure to X-rays or gamma

OLEGan [10]

Answer:C

Explanation:

just did the quiz

8 0

3 years ago

Read 2 more answers

Noah is loading the ark and the last animal on board is a stubborn 1500-kg elephant who refuses to budge. Noah and his family pu

Oxana [17]

The coefficient of sliding friction is 0.514

Explanation:

We start by writing the equations of motion of the elephant along the two directions, parallel and perpendicular, to the incline.

Along the parallel direction we have:

$F- mg sin \theta - \mu_k R = ma$ (1)

where :

F = 10,000 N is the force applied by Noah

$mg sin \theta$ is the component of the weight parallel to the incline, where:

m is the mass

g = 9.8 m/s^2 the acceleration of gravity

$\theta=10^{\circ}$ is the angle of incline

$\mu_k R$ is the force of friction, where:

$\mu_k$ is the coefficient of friction

R is the normal reaction

and a is the acceleration

Perpendicular direction:

$R-mg cos \theta =0$ (2)

where $mg cos \theta$ is the component of the weight perpendicular to the incline

From (2) we find

$R=mg cos \theta$

And substituting into (1)

$F-mg sin \theta - \mu_k mg cos \theta = ma$

We know that the elephant moves at constant speed, so the acceleration is zero:

a = 0

So the equation becomes

$F-mg sin \theta - \mu_k mg cos \theta=0$

And we can re-arrange it to find the coefficient of friction:

$F-mg sin \theta - \mu_k mg cos \theta=0\\\mu_k = \frac{F-m g sin \theta}{mg cos \theta}=\frac{10000-(1500)(9.8)(sin 10)}{(1500)(9.8)(cos 10)}=0.514$

Learn more about friction and inclined planes:

brainly.com/question/5884009

#LearnwithBrainly

4 0

3 years ago

A rugby player sits on a scrum machine that weighs 200 Newtons. Given that the coefficient of static friction is 0.67, the coeff

Trava [24]

a. 850 N is the minimum force needed to get the machine/player system moving, which means this is the maximum magnitude of static friction between the system and the surface they stand on.

By Newton's second law, at the moment right before the system starts to move,

• net horizontal force

∑ F[h] = F[push] - F[s. friction] = 0

• net vertical force

∑ F[v] = F[normal] - F[weight] = 0

and we have

F[s. friction] = µ[s] F[normal]

It follows that

F[weight] = F[normal] = (850 N) / (0.67) = 1268.66 N

where F[weight] is the combined weight of the player and machine. We're given the machine's weight is 200 N, so the player weighs 1068.66 N and hence has a mass of

(1068.66 N) / g ≈ 110 kg

b. To keep the system moving at a constant speed, the second-law equations from part (a) change only slightly to

∑ F[h] = F[push] - F[k. friction] = 0

∑ F[v] = F[normal] - F[weight] = 0

so that

F[k. friction] = µ[k] F[normal] = 0.56 (1268.66 N) = 710.45 N

and so the minimum force needed to keep the system moving is

F[push] = 710.45 N ≈ 710 N

4 0

2 years ago