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3 years ago

Five men push a stalled car with an average force of 400 N per person. Find the mass of the

Physics

1 answer:

timama [110]3 years ago

4 0

The mass of the car is 2000 kg

Explanation:

We can solve this problem by using Newton's second law of motion, which states that the net force acting on an object is equal to the product between the mass of the object and its acceleration:

$\sum F = ma$

where

$\sum F$ is the net force

m is the mass

a is the acceleration

In this problem, we have:

$a=1 m/s^2$ is the acceleration of the car

Each person applies a force of 400 N, and there are five men, so the total force applied is

$\sum F = 5\cdot 400 N = 2000 N$

Therefore, the mass of the car is:

$m=\frac{\sum F}{a}=\frac{2000 N}{1 m/s^2}=2000 kg$

Learn more about Newton's second law of motion:

brainly.com/question/3820012

#LearnwithBrainly

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A man is traveling on a bicycle at 14 m/s along a straight road that runs parallel to some railroad tracks. He hears the whistle

deff fn [24]

Answer:

Explanation:

b ) The problem is based on Doppler's effect of sound

f = f₀ x (V - v₀) /( $V+v_s$ )

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778 = 840 x (340 - 14)/ (340 + $v_s$ )

340 + $v_s$ = 341.18

$v_s$ = 1.18 m /s

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a )

For a stationary observer v₀ = 0

f = f₀ x V /( $V+v_s$ )

= 840 x 340 / (340 + 1.180)

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6 0

2 years ago

Atoms in a solid are not stationary, but vibrate about their equilibrium positions. Typically, the frequency of vibration is abo

hoa [83]

To develop this problem it is necessary to use the equations of description of the simple harmonic movement in which the acceleration and angular velocity are expressed as a function of the Amplitude.

Our values are given as

$f = 4.11 *10^{12} Hz$

$A = 1.23 * 10^{-11}m$

The angular velocity of a body can be described as a function of frequency as

$\omega = 2\pi f$

$\omega = 2\pi 4.11 *10^{12}$

$\omega=2.582*10^{13} rad/s$

PART A) The expression for the maximum angular velocity is given by the amplitude so that

$V = A\omega$

$V =( 1.23 * 10^{-11})(2.582*10^{13})$

$V = = 317.586m/s$

PART B) The maximum acceleration on your part would be given by the expression

$a = A \omega^2$

$a =( 1.23 * 10^{-11})(2.582*10^{13})^2$

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3 years ago

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ch4aika [34]

Incomplete question. However, I provided a brief about Kinetic energy generation.

Explanation:

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2 years ago

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natta225 [31]

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2 years ago

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OlgaM077 [116]

Answer:

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Explanation:

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2 years ago