Science

The period T of a pendulum of length L is measured to determine g at the surface of Earth. The equation used is T=2π√L/g. The ma

saul85 [17]

Answer:

C: Variation in the value of g as the pendulum bob moves along its arc.

Explanation:

The formula for period of a simple pendulum is given by;

T = 2π√(L/g)

Where;

L is length

g is acceleration due to gravity

Now, from this period equation, it is clear that the only thing that can affect the period of a simple pendulum are changes to its length and acceleration due to gravity.

Looking at the options, the only one that talks about either the length or gravity as being potential causes of the error is option C

4 0

3 years ago

A centrifuge in a medical laboratory rotates at an angular speed of 3,650 rev/min. when switched off, it rotates through 48.0 re

AlladinOne [14]

First of all we need to convert everything into SI units.

Let's start with the initial angular speed, $\omega _i = 3650 rev/min$ . Keeping in mind that
$1 rev = 2 \pi rad$
$1 min=60 s$
we have
$\omega _i = 3650 \frac{rev}{min} \cdot \frac{2 \pi rad/rev}{60 s/min} =382.0 rad/s$

And we should also convert the angle covered by the centrifuge:
$\theta = 48.0 rev= 48.0 rev \cdot 2 \pi \frac{rad}{rev}=301.4 rad$

This is the angle covered by the centrifuge before it stops, so its final angular speed is $\omega_f =0$ .

To solve the problem we can use the equivalent of
$2aS = v_f^2 -v_i^2$
of an uniformly accelerated motion but for a rotational motion. It will be
$2 \alpha \theta = \omega_f^2-\omega_i^2$
And by substituting the numbers, we can find the value of $\alpha$ , the angular acceleration:
$\alpha=- \frac{\omega_i^2}{2 \theta}=- \frac{(382 rad/s)^2}{2 \cdot 301.4 rad}=-242.1 rad/s^2$

4 0

3 years ago

A scientist collected the following data, which show how the pressure of water vapor changes with temperature.

den301095 [7]

Answer:

Make a graph for better visual representation.

Explanation:

Presenting data like that would require someone to see the increase. The best way would be a graph to be shown, to really show the impact by the line going up in the graph.

4 0

3 years ago

Read 2 more answers

you kick a soccer ball straight up into the air with a speed of 21.2 m/s. How long does it take he soccer ball to reach its high

stealth61 [152]

About 20-30 secs to reach its full point

5 0

3 years ago

Suppose you are chatting with your friend, who lives on the moon. He tells you he has just won a Newton of gold in a contest. Ex

lisabon 2012 [21]

Answer:

The friend on moon is richer.

Explanation:

The value of acceleration due to gravity changes from planet to planet. So the weight of 1 Newton of gold carries different mass on different places. So we need to calculate the mass of gold that both persons have.

FRIEND ON MOON:

W₁ = m₁g₁

where,

W₁ = Weight of Gold won by friend on moon = 1 N

m₁ = mass of gold won by friend on moon = ?

g₁ = acceleration due to gravity on moon = 1.625 m/s²

Therefore,

1 N = m₁(1.625 m/s²)

m₁ = 0.62 kg

ON EARTH:

W₂ = m₂g₂

where,

W₂ = Weight of Gold won by me on Earth = 1 N

m₂ = mass of gold won by me on Earth = ?

g₂ = acceleration due to gravity on Earth = 9.8 m/s²

Therefore,

1 N = m₁(9.8 m/s²)

m₁ = 0.1 kg

Since, the friend on moon has greater mass of gold than me.

Therefore, the friend on moon is richer.

5 0

3 years ago