Solve the simultaneous equations

Porfabor necesito ayuda en la esta pregunta. ¿Encuentra cuatro pares ordenados de la siguiente función? f(x) = X3 – 2X2 – 2

zlopas [31]

Answer:

(0, -2), (1, -3), (2, -2) y (3, 7) son pares ordenados de $f(x) = x^{3}-2\cdot x^{2}-2$ .

Step-by-step explanation:

Un par ordenado es un elemento de la forma $(x,f(x))$ , donde $x$ es un elemento del dominio de la función, mientras $f(x)$ es la imagen de la función evaluada en $x$ . Entonces, un par ordenado que está contenido en la citada función debe satisfacer la siguiente condición:

La imagen de la función existe para un elemento dado del dominio. Esto es:

$x \rightarrow f(x)$

Dado que $f(x)$ es una función polinómica, existe una imagen para todo elemento $x$ . Ahora, se eligen elementos arbitrarios del dominio para determinar sus imágenes respectivas:

x = 0

$f(0) = 0^{3}-2\cdot (0)^{2}-2$

$f(0) = -2$

(0, -2) es un par ordenado de $f(x) = x^{3}-2\cdot x^{2}-2$ .

x = 1

$f(1) = 1^{3}-2\cdot (1)^{2}-2$

$f(1) = -3$

(1, -3) es un par ordenado de $f(x) = x^{3}-2\cdot x^{2}-2$ .

x = 2

$f(2) = 2^{3}-2\cdot (2)^{2}-2$

$f(2) = -2$

(2, -2) es un par ordenado de $f(x) = x^{3}-2\cdot x^{2}-2$ .

x = 3

$f(3) = 3^{3}-2\cdot (3)^{2}-2$

$f(3) = 7$

(3, 7) es un par ordenado de $f(x) = x^{3}-2\cdot x^{2}-2$ .

(0, -2), (1, -3), (2, -2) y (3, 7) son pares ordenados de $f(x) = x^{3}-2\cdot x^{2}-2$ .

6 0

3 years ago

Suppose that each time Giannis Antetokounmpo shoots a free throw, he has a 3/4 probability of success. If Giannis shoots three f

GREYUIT [131]

Answer:

84.38% probability that he succeeds on at least two of them

Step-by-step explanation:

For each free throw, there are only two possible outcomes. Either Giannis makes it, or he does not. The free throws are independent. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

He has a 3/4 probability of success.

This means that $p = \frac{3}{4} = 0.75$

Giannis shoots three free throws

This means that $n = 3$

What is the probability that he succeeds on at least two of them

$P(X \geq 2) = P(X = 2) + P(X = 3)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 2) = C_{3,2}.(0.75)^{2}.(0.25)^{1} = 0.4219$

$P(X = 3) = C_{3,3}.(0.75)^{3}.(0.25)^{0} = 0.4219$

$P(X \geq 2) = P(X = 2) + P(X = 3) = 0.4219 + 0.4219 = 0.8438$

84.38% probability that he succeeds on at least two of them

6 0

3 years ago

I WILL GIVE BRAINLIEST. What is the justification for each step in solving the inequality?

LuckyWell [14K]

Heres all of them including the finished one.. just in case
75x - 35 ≥ 77x + 63 + 4  Distributive property.
75x -35 ≥ 77x + 67  Combine like terms.
-2x - 35 ≥ 67 Subtraction property of equality.
-2x ≥ 102  Addition property of equality.
<span>x ≤ 51  Division property of equality.

</span>

8 0

3 years ago

Read 2 more answers

Gabriel is at the grocery store, and wants to figure out his total cost before he gets to the register. He bought 2. 5 pounds of

katovenus [111]

The equation is 2.5x + 2y - 2 = 0.

<h2>Linear system</h2>

It is a system of an equation in which the highest power of the variable is always 1. A one-dimension figure that has no width. It is a combination of infinite points side by side.

Given

He bought 2.5 pounds of apples that are x dollars a pound.

And 2 bags of lettuce for y dollars each.

The total cost is $2.

The equation of this.

<h3>How to find the equation?</h3>

He bought 2.5 pounds of apples that are x dollars a pound.

Then the expression is 2.5x

And 2 bags of lettuce for y dollars each.

Then the expression is 2y

The total cost is $2.

Then the expression will be

2.5x + 2y = 2

2.5x + 2y - 2 = 0

Thus the equation is 2.5x + 2y - 2 = 0.

More about the linear system link is given below.

brainly.com/question/20379472

8 0

2 years ago

HELPPP!!!! Both questions are incredibly confusing to me !!!!!

Darya [45]

Answer:

Step-by-step explanation:

I'm going to start with problem 3. You need to become familar with the kind of tricks teachers play on you.

Problem 3 depends on getting RS = RW.

RT = RT Reflexive property

<STR = <WTR A straight line having 1 rt angle actually has 2

ST = TU They are marked as equal

Triangle STR=Triangle WTR SAS

RS = RW Corresponding parts of = triangles are =

8x = 6x + 5 Subtract 6x from both sides

8x -6x = 6x - 6x + 5 Combine

2x = 5 Divide by 2

2x/2 = 5/2

x = 2.5

RU = 6*2.5 + 5

RU = 15 + 5

RU = 20

Now we can play with Question 4.

This question depends on the method used in three, although not entirely.

What you need to know is that W is on RT when you take a ruler and make RT longer. You can put W anywhere as long as it is on RT when it is made longer.

Directions

Make RT longer. Draw down and to your right.

Put a point anywhere on the length starting at T. Label this new point as W. There's your W. It goes anywhere on the part of RT made longer.

Draw UW.

Label UW as 8

Now draw another line from S to W. Guess what? By the methods used in question 3, it's also 8. So SW = 8

TW = TW Reflexive

<UTW = STW Same reason as in 3. UtW is a right angle

UT = ST Given (the marking tells you so.

ΔUTW = ΔSTW SAS

UW = SW Corresponding parts of = triangles are =

SW = 8

7 0

2 years ago