First find all of the factors of 6. They are 1, 2, 3, and 6. The probability of anything is the number of possible outcomes divided by the total number of outcomes. The possible outcomes for factors of 6 are 1, 2, 3, and 6. There are 4. The total number of outcomes is 8, listing all of the integers 1-8. Therefore, the probability is 4/8 or 1/2. This can also be written as 50%.
Answer:
{1,2,3,4}
Step-by-step explanation:
cant be zero, also got it right on edge 2020
B...
|-24+6|=18
Same for the other one.
Vertical asymptotes are
vertical lines which correspond to the zeroes of the denominator of a
rational function<span>.
(They can also arise in other contexts, such as logarithms, but you'll
almost certainly first encounter asymptotes in the context of rationals.) I'll give you an example:
</span>
This is a rational function.
More to the point, this is a fraction. Can you have a zero in the denominator
of a fraction? No. So if I set the denominator of the above fraction equal
to zero and solve, this will tell me the values that x
cannot be:
x2
– 5x – 6 = 0<span>
</span>(x
– 6)(x + 1) = 0<span>
</span>x
= 6 or –1
So x
cannot be
6 or –1,
because then I'd be dividing by zero.
<span>
<span><span>
<span>
</span></span><span><span /><span>
</span>
</span>
</span></span>
The domain is the set
of all x-values
that I'm allowed to use. The only values that could be disallowed are
those that give me a zero in the denominator. So I'll set the denominator
equal to zero and solve.
<span>x2
+ 2x – 8 = 0</span><span>
</span><span>(x
+ 4)(x – 2) = 0</span><span>
</span><span>x
= –4</span> or <span>x
= 2</span>
Since I can't have a
zero in the denominator, then I can't have <span>x
= –4</span> or <span>x
= 2</span> in the domain.
This tells me that the vertical asymptotes (which tell me where the
graph can <span>not
</span>go) will be at the
values <span>x
= –4</span> or <span>x
= 2</span>.
domain:
<span>
</span><span>vertical
asymptotes: <span>x
= –4</span>,<span>
2</span></span>
<span>
<span>
</span></span>
What is the question for the problem are you trying to figure out area or perhaps perimeter and of what the shaded or non shaded next time include that in your answer.