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Alexandra [31]
3 years ago
9

Please help. More to come later.

Mathematics
2 answers:
ICE Princess25 [194]3 years ago
7 0
4z I hope i help you some
IrinaK [193]3 years ago
6 0
3z-4+2z+5
3z+2z-4+5
5z+1
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Please help <br> Whoever gets right will receive brainliest <br><br> No links or spam
777dan777 [17]

Step-by-step explanation:

Area of a circle = πr²

r = 6 mm (given)

Area = π(6)² = 36π mm².

3 0
3 years ago
Read 2 more answers
8/3 as a terminating decimal
krek1111 [17]
The Answer is 0.375 hope this helps u
8 0
3 years ago
A sphere has a radius of 3.5 centimeters.
Snezhnost [94]
V= \frac{4}{3} \pi r^3= \frac{4}{3} \cdot \pi  \cdot 3.5^3 \approx 57.2 \pi

Answer is <span>57.2π </span>
4 0
3 years ago
Subtract and simplify. Show work please!
ra1l [238]

1) Final expression: +7y^2-6y-17

2) Final expression: 21x^3-46x^2+59x-30

Step-by-step explanation:

1)

The first expression is

(-2y^2-11y-7)-(-9y^2-5y+10)

First, we remove the 2nd bracket by changing the sign of all the terms inside:

-2y^2-11y-7-+9y^2+5y-10

Now we group the terms with same degree together:

(-2y^2+9y^2)+(-11y+5y)+(-7-10)

Now we solve the expression in each brackets:

(-2y^2+9y^2)+(-11y+5y)+(-7-10)=\\+7y^2-6y-17

So, this is the final expression.

2)

The second expression is

(7x-6)(3x^2-4x+5)

We apply the distributive property, so we rewrite the expression as follows:

(7x-6)(3x^2-4x+5)=7x(3x^2-4x+5)-6(3x^2-4x+5)

Solving both brackets,

7x(3x^2-4x+5)-6(3x^2-4x+5)=\\21x^3-28x^2+35x-18x^2+24x-30

Now we group terms of same degree together:

21x^3-28x^2+35x-18x^2+24x-30=\\21x^3+(-28x^2-18x^2)+(35x+24x)-30

And solving each bracket,

21x^3+(-28x^2-18x^2)+(35x+24x)-30=\\21x^3-46x^2+59x-30

So, this is the final expression.

Learn how to simplify expressions:

brainly.com/question/7014769

brainly.com/question/11007572

brainly.com/question/11334714

#LearnwithBrainly

3 0
3 years ago
The quantity demanded x of a certain brand of DVD player is 3000/week when the unit price p is $485. For each decrease in unit p
ANTONII [103]

Answer:

Demand Equation: q = 15125 - 25p.

Supply Equation: 80p - 24000 = 9q.

Equilibrium Price: $525.

Equilibrium Quantity: 2000 units.

Step-by-step explanation:

To solve this question, first, the demand equation has to be calculated. Let price be on the y-axis and quantity by on the x-axis. It is given that p = $485 when q = 3000 units. This can also be written as (q₁, p₁) = (3000, 485). It is also given that when the price goes down by $20, the quantity increases by 500 units. Therefore, (q₂, p₂) = (3500, 465). Due to the statement "For each decrease in unit price of $20 below $485, the quantity demanded increases by 500 units", the demand function will be linear i.e. a straight line. This is because the word "for each" has been used. Therefore, finding the equation of the demand function:

(p - p₁)/(q - q₁) = (q₂ - q₁)/(p₂ - p₁).

(p - 485)/(q - 3000) = (465 - 485)/(3500 - 3000).

(p - 485)/(q - 3000) = (-20)/(500).

(p - 485)/(q - 3000) = -1/25.

25*(p - 485) = -1*(q - 3000).

25p - 12125 = -q + 3000.

25p + q = 15125.

q = 15125 - 25p. (Demand Equation).

Second, find the supply equation. It is given that the suppliers will not sell the product below or at the price of $300. Therefore, (q₁, p₁) = (0, 300). Also, the suppliers will sell 2000 units if the price is $525. Therefore, (q₂, p₂) = (2000, 525). Since it is mentioned that supply equation is linear, therefore:

(p - p₁)/(q - q₁) = (q₂ - q₁)/(p₂ - p₁).

(p - 300)/(q - 0) = (525 - 300)/(2000 - 0).

(p - 300)/(q) = (225)/(2000).

(p - 300)/(q) = 9/80.

80*(p - 300) = 9*(q).

80p - 24000 = 9q. (Supply Equation).

Equilibrium exists when demand = supply. This means that the demand and the supply equations have to be solved simultaneously. Therefore, put demand equation in supply equation:

80p - 24000 = 9(15125 - 25p).

80p - 24000 = 136125 - 225p.

305p = 160125.

p = $525.

Put p = $525 in demand equation:

q = 15125 - 25p.

q = 15125 - 25(525).

q = 15125 - 13125.

q = 2000 units.

To summarize:

Demand Equation: q = 15125 - 25p!!!

Supply Equation: 80p - 24000 = 9q!!!

Equilibrium Price: $525!!!

Equilibrium Quantity: 2000 units!!!

8 0
3 years ago
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