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yanalaym [24]
2 years ago
11

Mike Mowed 5 Lawns last week and 7 lawns this week and earned $180. He earned the same amount mowing each lawn. How much did Mik

e earns mowing each lawn?
Mathematics
1 answer:
Lilit [14]2 years ago
5 0

Answer:

15

Step-by-step explanation:

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Determine the equation of the linear graph that passes through (-2,3) and (4,6). State your answer in the
Lena [83]

The linear equation is y = 4 + 0.5x

<h3>How to determine the equation?</h3>

The points are given as: (-2,3) and (4,6)

The equation is then calculated using:

y = \frac{y_2 -y_1}{x_2 -x_1} *(x - x_1) + y_1

Substitute the known values

y = \frac{6-3}{4+2} *(x+2) + 3

Evaluate

y = 0.5 *(x+2) + 3

Expand

y = 0.5x + 1 + 3

Evaluate the sum

y = 0.5x + 4

Rewrite as:

y = 4 + 0.5x

Hence, the equation is y = 4 + 0.5x

Read more about linear equations at:

brainly.com/question/14323743

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3 0
2 years ago
One-third is ___________ pieces of a whole
Mkey [24]
One-third is one out of three pieces of a whole.

I hope this helps, please Brainliest me, and have a great day! :D
4 0
3 years ago
Read 2 more answers
what is the solution to the system of equations shien on the graph? A.(0,5) B.(-2,1) C.(0,-1) D.(1,-2)
VLD [36.1K]

Solution is where the lines intersect. It's  is (-2 , 1)

Answer is B.(-2,1)

3 0
3 years ago
In a certain community, 36 percent of the families own a dog and 22 percent of the families that own a dog also own a cat. In ad
zysi [14]

Answer:  a) 0.0792   b) 0.264

Step-by-step explanation:

Let Event D = Families own a dog .

Event C = families own a cat .

Given : Probability that families own a dog : P(D)=0.36

Probability that families own a dog also own a cat : P(C|D)=0.22

Probability that families own a cat : P(C)= 0.30

a) Formula to find conditional probability :

P(B|A)=\dfrac{P(A\cap B)}{P(A)}\\\\\Rightarrow P(A\cap B)=P(B|A)\times P(A)   (1)

Similarly ,

P(C\cap D)=P(C|D)\times P(D)\\\\=0.22\times0.36=0.0792

Hence, the probability that a randomly selected family owns both a dog and a cat : 0.0792

b) Again, using (2)

P(D|C)=\dfrac{P(C\cap D)}{P(C)}\\\\=\dfrac{0.0792}{0.30}=0.264

Hence, the conditional probability that a randomly selected family owns a dog given that it owns a cat = 0.264

5 0
3 years ago
I have trouble understanding word problems. May I please have help with number 15? Thank you very much!
guapka [62]
Basically you do fractions side by side. so, 6/3=15/h and then cross multiply to get your answer so that would give you 3h=80, then divide 80÷3
5 0
3 years ago
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