The linear equation is y = 4 + 0.5x
<h3>How to determine the equation?</h3>
The points are given as: (-2,3) and (4,6)
The equation is then calculated using:

Substitute the known values

Evaluate
y = 0.5 *(x+2) + 3
Expand
y = 0.5x + 1 + 3
Evaluate the sum
y = 0.5x + 4
Rewrite as:
y = 4 + 0.5x
Hence, the equation is y = 4 + 0.5x
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One-third is one out of three pieces of a whole.
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Solution is where the lines intersect. It's is (-2 , 1)
Answer is B.(-2,1)
Answer: a) 0.0792 b) 0.264
Step-by-step explanation:
Let Event D = Families own a dog .
Event C = families own a cat .
Given : Probability that families own a dog : P(D)=0.36
Probability that families own a dog also own a cat : P(C|D)=0.22
Probability that families own a cat : P(C)= 0.30
a) Formula to find conditional probability :
(1)
Similarly ,

Hence, the probability that a randomly selected family owns both a dog and a cat : 0.0792
b) Again, using (2)

Hence, the conditional probability that a randomly selected family owns a dog given that it owns a cat = 0.264
Basically you do fractions side by side. so, 6/3=15/h and then cross multiply to get your answer so that would give you 3h=80, then divide 80÷3