Answer:
x = 28.01t,
y = 10.26t - 4.9t^2 + 2
Step-by-step explanation:
If we are given that an object is thrown with an initial velocity of say, v1 m / s at a height of h meters, at an angle of theta ( θ ), these parametric equations would be in the following format -
x = ( 30 cos 20° )( time ),
y = - 4.9t^2 + ( 30 cos 20° )( time ) + 2
To determine " ( 30 cos 20° )( time ) " you would do the following calculations -
( x = 30 * 0.93... = ( About ) 28.01t
This represents our horizontal distance, respectively the vertical distance should be the following -
y = 30 * 0.34 - 4.9t^2,
( y = ( About ) 10.26t - 4.9t^2 + 2
In other words, our solution should be,
x = 28.01t,
y = 10.26t - 4.9t^2 + 2
<u><em>These are are parametric equations</em></u>
Answer:
d=4.5t
Step-by-step explanation:
in two hours, Francine went 9 miles
9/2=4.5
the distance equals 4.5 times each cycling time.
d=4.5t
Answer:
The average rate of change from x=0 to x=1 for f(x) is 0.
Step-by-step explanation:
We are given the function 
.
Now, the rate average rate of change of a function from 
to 
is given by 
.
As, we need the rate of change from x = 0 to x = 1.
So, we will find the values of f(0) and f(1).
i.e. 
i.e. f(0) = 3
and 
i.e. 
i.e. f(1) = 3
Thus, the rate of change from x=0 to x=1 is 
i.e. 
i.e. 0
Hence, the average rate of change from x=0 to x=1 for f(x) is 0.
3c-d
3c-(-c+7)
3c+c-7
4c-7
Final answer: 4c-7
