The first step begins with: A. the mouth.
Photosynthesis and cellular respiration are opposites
The answers would be:
Genotype Phenotype
Tt Tall stemmed
tt Short stemmed
Genotypic ratio : 2:2 or 1:1
Phenotypic ratio: 2:2 or 1:1
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<u>You can read on to see how this was done:</u>
Tall stems (T) are dominant to short stems (t).
First figure out the genotypes of the parents. We have a short-stemmed plant and a heterozygous long-stemmed plant cross.
For short stem to occur, you need 2 pairs of short alleles. So the first parent would have a genotype of tt.
Heterozygous long-stemmed means that the parent has one of each allele. So the genotype of the second parent would be, Tt.
Now we can make our Punnett Square.
tt x Tt
<u> t t </u>
<u>T | Tt | Tt</u>
<u>t | tt | tt</u>
Let's list down the genotypes and phenotypic results.
Genotype no. Phenotype
Tt 2 Tall stemmed
tt 2 Short stemmed
So from that we can answer the other questions:
Genotypic ratio : 2:2 or 1:1
Phenotypic ratio: 2:2 or 1:1
Answer:
Produce multiple polypeptide sequences from a single primary transcript.
Explanation:
Some genes produce more than one type of protein since the primary transcript encoded by these genes undergoes alternative splicing. These genes mostly have one segment that can serve either as intron or exon. Also called differential splicing, alternative splicing removes the segment as intron but retains it as an exon.
Splicing of the single primary transcript in different ways produces more than one version of mRNA from a single primary transcript encoded by a single gene. The alternative splicing allows the cells to produce multiple types of troponin proteins from single genes. These different troponin regulation muscle contraction in different muscles
Answer:
none of the males or females could be colorblind, assuming that this question is referring to x-linked recessive inheritance patterns.
Explanation:
if it is an x linked recessive trait, then the male's genotype is, with (b) representing colorblindness and (B) representing normal vision. the female, who is h o m o z y g o u s for normal vision, would have the genotype.
It would be impossible for the dad to pass on his colorblind gene to a son, because he can only pass a Y chromosome to the son. and a daughter would get the colorblind gene, but the normal gene donated by the mom would dominate it so the daughter could not actually be colorblind
