Ask question

Ask question

All categories

3 years ago

14

a scale drawing of a building needs to be made using the scale 1 in = 190 ft. how tall will the builging in the scale drawing be

if the building is 570 ft tall

1 answer:

Artist 52 [7]3 years ago

3 0

Answer:

$\boxed{\text{3 in}}$

Step-by-step explanation:

1 in = 190 ft

x in = 570 ft

We can use ratio and proportion to solve this problem.

$\begin{array}{cccl}\dfrac{1}{x} & = & \dfrac{190}{570} & \\\\570 & = & 190x & \text{Mutiplied by lowest common denominator (570x)}\\3 & = & x & \text{Divided each side by 3}\\\end{array}$

The building will be $\boxed{\textbf{3 in}}$ tall in the scale drawing.

You might be interested in

How do I solve 1.25÷30

Shtirlitz [24]

Calculator lolololol nah joking first

5 0

3 years ago

Read 2 more answers

I have nooooo clue, please help

Aleksandr-060686 [28]

Answer:

case a) $x^{2}=3y$ ----> open up

case b) $x^{2}=-10y$ ----> open down

case c) $y^{2}=-2x$ ----> open left

case d) $y^{2}=6x$ ----> open right

Step-by-step explanation:

we know that

1) The general equation of a vertical parabola is equal to

$y=a(x-h)^{2}+k$

where

a is a coefficient

(h,k) is the vertex

If a>0 ----> the parabola open upward and the vertex is a minimum

If a<0 ----> the parabola open downward and the vertex is a maximum

2) The general equation of a horizontal parabola is equal to

$x=a(y-k)^{2}+h$

where

a is a coefficient

(h,k) is the vertex

If a>0 ----> the parabola open to the right

If a<0 ----> the parabola open to the left

Verify each case

case a) we have

$x^{2}=3y$

so

$y=(1/3)x^{2}$

$a=(1/3)$

so

$a>0$

therefore

The parabola open up

case b) we have

$x^{2}=-10y$

so

$y=-(1/10)x^{2}$

$a=-(1/10)$

$a$

therefore

The parabola open down

case c) we have

$y^{2}=-2x$

so

$x=-(1/2)y^{2}$

$a=-(1/2)$

$a$

therefore

The parabola open to the left

case d) we have

$y^{2}=6x$

so

$x=(1/6)y^{2}$

$a=(1/6)$

$a>0$

therefore

The parabola open to the right

3 0

2 years ago

How would you find the area of the shaded region?

Whitepunk [10]

Answer:

The Area of the shaded region = (Area of the largest circle) – (Area of the circle with radius 3) – (Area of the circle with radius 2). Whatever is left over is the shaded region. The diameter of the largest circle is 10, so its radius is 5 and thus its area is 25π. SO do this in that problem and you will get the answer.

Step-by-step explanation:

pls give me brainliest

3 0

3 years ago

Your grandparents invested $2,000 for you on the day you were born. How much will this investment be worth on your 25th birthday

algol [13]

We know that, Amount in Compound interest is given by :

$\bigstar \ \ \boxed{\sf{Amount = Principal\bigg(1 + \dfrac{Rate \ of \ Interest}{100}\bigg)^{Time \ Period}}}$

Given : Principal = $2000

Given : Annual yield is 5% and the interest is compounded quarterly

It means : Interest is compounded 4 times in a year

$\implies \sf{Rate \ of \ Interest = \dfrac{R}{4} = \dfrac{5}{4}}$

$\sf{\implies Time \ period = (25 \times 4) = 100}$

Substituting all the values in the formula, we get :

$\implies \sf{Amount = 2000\bigg(1 + \dfrac{\dfrac{5}{4}}{100}\bigg)^{100}}$

$\implies \sf{Amount = 2000\bigg(1 + \dfrac{5}{400}\bigg)^{100}}$

$\implies \sf{Amount = 2000\bigg(1 + \dfrac{1}{80}\bigg)^{100}}$

$\implies \sf{Amount = 2000\bigg(\dfrac{81}{80}\bigg)^{100}}$

$\implies \sf{Amount = 2000 \times (1.0125)^{100}}$

$\implies \sf{Amount = 2000 \times 3.463}}$

$\implies \sf{Amount = 6926.8}$

8 0

3 years ago

Please help for brainliest answer

melamori03 [73]

Frequency for success is 244
Relative is 0.61
Relative for fail is 0.15

7 0

2 years ago