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abruzzese [7]
2 years ago
15

(pls ignore this. XXXXX)

Mathematics
2 answers:
Gelneren [198K]2 years ago
6 0

Answer:

..................................

juin [17]2 years ago
4 0

Answer:

Why

Step-by-step explanation:

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HELP. How long is the minor axis for the ellipse shown below?
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Given:

The equation of ellipse is

\dfrac{(x+4)^2}{25}+\dfrac{(y-1)^2}{16}=1

To find:

The length of the minor axis.

Solution:

The standard form of an ellipse is

\dfrac{(x-h)^2}{a^2}+\dfrac{(y-k)^2}{b^2}=1      ...(i)

where, (h,k) is center, if a>b, then 2a is length of major axis and 2b is length of minor axis.

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\dfrac{(x+4)^2}{25}+\dfrac{(y-1)^2}{16}=1      ...(ii)

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b^2=16

Taking square root on both sides.

b=\pm 4

Consider only positive value of b because length cannot be negative.

b=4

Now,

Length of minor axis = 2b

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2 years ago
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Answer:

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Step-by-step explanation:

If binomial (x - 6) and trinomial (-2x² + x + 9) are the factors of a polynomial then their multiplication will be equal to the polynomial.

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Therefore, Option (3) will be the correct option.

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