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3 years ago

Q #...10 somebody help me

Mathematics

2 answers:

GenaCL600 [577]3 years ago

8 0

The slope of a line can be found, given two points, as follows:

$P_{1}(-5.5,6.1) \\ \\ P_{2}(-2.5,3.1) \\ \\ m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}} \\ \\ m=\frac{3.1-6.1}{-2.5-(-5.5)}=-1$

So this slope tells us the direction of a line and represents the vertical change divided by the horizontal change.

Nikitich [7]3 years ago

3 0

It is -1, at least thats what i got i hope this helped

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Suppose that two players, R and C, write down letters of the alphabet. If both write vowels or both write consonants, then th

vladimir2022 [97]

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Step-by-step explanation:

[Player R, Player C] cases & outcomes :-

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5 0

3 years ago

If f and g are differentiable functions for all real values of x such that f(1) = 4, g(1) = 3, f '(3) = −5, f '(1) = −4, g '(1)

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Answer:

h'(1)=0

Step-by-step explanation:

We use the definition of the derivative of a quotient:

If $h(x)=\frac{f(x)}{g(x)}$ , then:

$h'(x)=\frac{f'(x)*g(x)-f(x)*g'(x)}{(g(x))^2}$

Since in our case we want the derivative of $h(x)$ at the point x = 1, which is indicated by: h'(1), we need to evaluate the previous expression at x = 1, that is:

$h'(1)=\frac{f'(1)*g(1)-f(1)*g'(1)}{(g(1))^2}$

which, by replacing with the given numerical values:

$f(1) =4\\g(1)=3\\f'(1)=-4\\g'(1)=-3$

becomes:

$h'(1)=\frac{f'(1)*g(1)-f(1)*g'(1)}{(g(1))^2}=\\=\frac{-4*3-4*(-3)}{(3)^2}=\frac{-12+12}{9} =\frac{0}{9} =0$

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3 years ago