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3 years ago

Simplify. (5x^3y^2+x^2-6x^2y^3) - (3x^2y^3-4y^3+7x^2)

Mathematics

1 answer:

Zanzabum3 years ago

5 0

Answer:

Step-by-step explanation:

The initial expression is:

$(5x^{3}y^{2}+x^{2}-6x^{2}y^{3})-(3x^{2}y^{3}-4y^{3}+7x^{2})$

Using BEMDAS (Brackets - Exponents - Multiplication - Division - Addition -Subtraction), we first start with brackets:

$5x^{3}y^{2}+x^{2}-6x^{2}y^{3}-3x^{2}y^{3}+4y^{3}-7x^{2}$

Remember that if there is a negative sign, it will change the signs of the terms within the brackets.

Then, collecting like terms:

$5x^{3}y^{2}-9x^{2}y^{3}+4y^{3}-6x^{2}$

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tamaranim1 [39]

Answer:

Your(my) number is 40

Step-by-step explanation:

I. Given 80/something, + 13, * 5 = 75 when x is something

So [ $\frac{80}{x}$ + 13 ]5 = 75

[ $\frac{400}{x}$ + 65] = 75

$\frac{400}{x}$ = 75 - 65

$\frac{400}{x}$ = 10

400 = 10x

x = 40

II. Prove by replace 40 in x

[(80/40) + 13]5 = 75

[2 + 13] 5 = 75

(15)5 = 75

75 = 75 true

Ask me for anything.

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2 years ago

4. (03.03 HC)

Kitty [74]

Answer:

A. yes, the data represents a function because u have no repeating x values. A function cannot have repeating x values...they can have repeating y values, just not the x ones

Step-by-step explanation:

B. table : (8,8)(12,12)(14,16)(16,16)

look at ur points...when x = 8, y = 8...so the table, when x = 8 has a

value of 8

relation : f(x) = 8x - 5....when x = 8

f(8) = 8(8) - 5

f(8) = 64 - 5

f(8) = 59....and the relation has a value of 59

Therefore, the relation has a greater value when x = 8 <==

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19 = 8x - 5

19 + 5 = 8x

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3 years ago

Of the 8760 hours in a year, most televisions are on for 2190 hours. What percent is this

Dimas [21]

Answer:

Hello!! Your answer is 25% I think!

Hope this helps!!

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2 years ago

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pochemuha

Answer:

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2 years ago

Find the sample size, n, needed to estimate the percentage of adults who have consulted fortune tellers. Use a 0.02 margin of er

Brrunno [24]

Answer: 2172

Step-by-step explanation:

Formula to find the sample size n , if the prior estimate of the population proportion(p) is known:

$n= p(1-p)(\dfrac{z^*}{E})^2$ , where E= margin of error and z* = Critical z-value.

Let p be the population proportion of adults have consulted fortune tellers.

As per given , we have

p= 0.20

E= 0.02

From z-table , the z-value corresponding to 98% confidence interval = z*=2.33

Then, the required sample size will be :

$n= 0.20(1-0.20)(\dfrac{2.33}{0.02})^2$

$n= 0.20(0.80)(116.5)^2$

$n= 2171.56\approx2172$

Hence, the required sample size = 2172

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2 years ago