Answer:
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Step-by-step explanation:
Given

--- distance from building
--- height of the building
Let the height of the building be H. So:


Make H the subject


The required height s:



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<em> --- approximately</em>
Although I don't see 1950, 1988, or 2010 on your model, I did calculate the average for 1972, 1982, 1992, and 2002: the average that I got was 1.6025 (this answer has not been rounded due to the fact that I don't know if you need to round it)
hope this helps
Similar to the last problem
y = x + 2
y + 3 = 2x
so we need to find which values fit
check out B and D - its one of those
Here you go <span> 1.17 × 10^</span><span>9
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