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tensa zangetsu [6.8K]
3 years ago
12

The angle y has the value? show how you solved it

Mathematics
1 answer:
andrew-mc [135]3 years ago
5 0

Answer:

x=76^o

y=104^o

Step-by-step explanation:

we know that

(y-28)=x ---> equation A (by alternate interior angles)

we have that

x+y=180 ---> by supplementary angles (form a linear pair)

x=180-y ----> equation B

substitute equation B in equation A

(y-28)=180-y

solve for y

y+y=180+28

2y=208

y=104^o

<em>Find the value of x</em>

x=180-104

x=76^o

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To solve this problem, you will use the distributive property to create an equation that can be rearranged and solved using the quadratic formula.

<h3>Distribute</h3>

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3x(x+6)=-10

3x^2+18x=-10

<h3>Rearrange</h3>

To create a quadratic equation, add 10 to both sides of the equation:

3x^2+18x+10=-10+10

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<h3>Use the Quadratic Formula</h3>

The quadratic formula is defined as:

\displaystyle x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}

The model of a quadratic equation is defined as ax² + bx + c = 0. This can be related to our equation.

Therefore:

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Set up the quadratic formula:

\displaystyle x=\frac{-18 \pm \sqrt{(18)^2 - 4(3)(10)}}{2(3)}

Simplify by using BPEMDAS, which is an acronym for the order of operations:

Brackets

Parentheses

Exponents

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Division

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Use BPEMDAS:

\displaystyle x=\frac{-18 \pm \sqrt{324 - 120}}{6}

Simplify the radicand:

\displaystyle x=\frac{-18 \pm \sqrt{204}}{6}

Create a factor tree for 204:

204 - 1, 2, 3, 4, 6, 12, 17, 34, 51, 68, 102 and 204.

The largest factor group that creates a perfect square is 4 × 51. Therefore, turn 204 into 4 × 51:

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Then, using the Product Property of Square Roots, break this into two radicands:

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Since 4 is a perfect square, it can be evaluated:

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To simplify further for easier reading, remove the multiplication symbol:

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Then, substitute for the quadratic formula:

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This gives us a combined root, which we should separate to make things easier on ourselves.

<h3>Separate the Roots</h3>

Separate the roots at the plus-minus symbol:

\displaystyle x=\frac{-18 + 2\sqrt{51}}{6}

\displaystyle x=\frac{-18 - 2\sqrt{51}}{6}

Then, simplify the numerator of the roots by factoring 2 out:

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Then, simplify the fraction by reducing 2/6 to 1/3:

\boxed{\displaystyle x=\frac{-9 + \sqrt{51}}{3}}

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The final answer to this problem is:

\displaystyle x=\frac{-9 + \sqrt{51}}{3}

\displaystyle x=\frac{-9 - \sqrt{51}}{3}

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