PLEASE I BEG OF YOU HELP ME

4 to the power of 5 × 3 to the power of 2

Rama09 [41]

Answer:

Step-by-step explanation:

Break down the equation first.1) 5(3)= 15

2)15 to the power of 2=225,because you have to multiply 15 by itself 2 times.

3)225 to the power of 4=2,562,890,625

Answer= 2,562,890,625

8 0

3 years ago

A ball is thrown vertically upward. After t seconds, its height h (in feet) is given by the function h(t)=72t-16t^2. After how l

galben [10]

Answer:

i coulnt answer this i love you

4 0

3 years ago

Read 2 more answers

Use variation of parameters to find a general solution to the differential equation given that the functions y1 and y2 are linea

Aleks [24]

Recall that variation of parameters is used to solve second-order ODEs of the form

y''(t) + p(t) y'(t) + q(t) y(t) = f(t)

so the first thing you need to do is divide both sides of your equation by t :

y'' + (2t - 1)/t y' - 2/t y = 7t

You're looking for a solution of the form

$y=y_1u_1+y_2u_2$

where

$u_1(t)=\displaystyle-\int\frac{y_2(t)f(t)}{W(y_1,y_2)}\,\mathrm dt$

$u_2(t)=\displaystyle\int\frac{y_1(t)f(t)}{W(y_1,y_2)}\,\mathrm dt$

and W denotes the Wronskian determinant.

Compute the Wronskian:

$W(y_1,y_2) = W\left(2t-1,e^{-2t}\right) = \begin{vmatrix}2t-1&e^{-2t}\\2&-2e^{-2t}\end{vmatrix} = -4te^{-2t}$

Then

$u_1=\displaystyle-\int\frac{7te^{-2t}}{-4te^{-2t}}\,\mathrm dt=\frac74\int\mathrm dt = \frac74t$

$u_2=\displaystyle\int\frac{7t(2t-1)}{-4te^{-2t}}\,\mathrm dt=-\frac74\int(2t-1)e^{2t}\,\mathrm dt=-\frac74(t-1)e^{2t}$

The general solution to the ODE is

$y = C_1(2t-1) + C_2e^{-2t} + \dfrac74t(2t-1) - \dfrac74(t-1)e^{2t}e^{-2t}$

which simplifies somewhat to

$\boxed{y = C_1(2t-1) + C_2e^{-2t} + \dfrac74(2t^2-2t+1)}$

4 0

3 years ago

HELP I NEED HELP ASAP HELP I NEED HELP ASAP HELP I NEED HELP ASAP HELP I NEED HELP ASAP HELP I NEED HELP ASAP

frozen [14]

Answer:

54 units squared

Step-by-step explanation:

hope this helped!

3 0

3 years ago

A dairy wishes to mix together 1,000 pints of milk that contains 8% butterfat.If the mixture is to be made from milk containing

3241004551 [841]

Answer:

800 pints of 5% butterfat and 200 pints of 20% butterfat is needed.

Step-by-step explanation:

Given:

A dairy wishes to mix together 1,000 pints of milk that contains 8% butterfat.

If the mixture is to be made from milk containing 5% butterfat, and cream

containing 20% butterfat.

Now, to find the pints of each is needed.

Let the pints of 5% butterfat be $x.$

And the pints of 20% butterfat be $y.$

So, the total pints of milk:

$x+y=1000$

$x=1000-y$ ......(1)

As, given:

1,000 pints of milk that contains 8% butterfat.

The mixture of milk containing 5% butterfat, and cream containing 20% butterfat.

According to question:

$5(x)+20(y)=8(1000)$

$5x+20y=8000$

Substituting the value of $x$ from equation (1):

$5(1000-y)+20y=8000$

$5000-5y+20y=8000$

$5000+15y=8000$

Subtracting both sides by 5000 we get:

$15y=3000$

Dividing both sides by 15 we get:

$y=200.$

The pints of 20% butterfat = 200 pints.

Now, to get the pints of 5% butterfat we put the value of $y$ in equation (1):

$x=1000-y$

$x=1000-200$

$x=800.$

The pints of 5% butterfat = 800 pints.

Therefore, 800 pints of 5% butterfat and 200 pints of 20% butterfat is needed.

8 0

3 years ago