Answer:
1 + 2sqrt(3)/3
Step-by-step explanation:
tan(30) = sqrt(3)/3
sin(90) = 1
tan(60) = sqrt(3)
cot(60) = 1/sqrt(3) = sqrt(3)/3
sqrt(3)/3 + 1 + sqrt(3)/3
1 + 2sqrt(3)/3
Answer:

It has one solution
Step-by-step explanation:
![14x + 12] = 0\\\\14x+12=0\\\mathrm{Subtract\:}12\mathrm{\:from\:both\:sides}\\14x+12-12=0-12\\\\Simplify\\14x=-12\\\\\mathrm{Divide\:both\:sides\:by\:}14\\\frac{14x}{14}=\frac{-12}{14}\\\\Simplify\\x=-\frac{6}{7}](https://tex.z-dn.net/?f=14x%20%2B%2012%5D%20%3D%200%5C%5C%5C%5C14x%2B12%3D0%5C%5C%5Cmathrm%7BSubtract%5C%3A%7D12%5Cmathrm%7B%5C%3Afrom%5C%3Aboth%5C%3Asides%7D%5C%5C14x%2B12-12%3D0-12%5C%5C%5C%5CSimplify%5C%5C14x%3D-12%5C%5C%5C%5C%5Cmathrm%7BDivide%5C%3Aboth%5C%3Asides%5C%3Aby%5C%3A%7D14%5C%5C%5Cfrac%7B14x%7D%7B14%7D%3D%5Cfrac%7B-12%7D%7B14%7D%5C%5C%5C%5CSimplify%5C%5Cx%3D-%5Cfrac%7B6%7D%7B7%7D)
5(700)+(50)+(4)that’s how you write it
Acceleration is simplified by assuming it is the constant -g
a=-g we integrate this with respect to time to get v...
v=-gt+C where C is the initial velocity in this case 14ft/s so
v=-gt+14 integrate again to get the height function
h=(-gt^2)/2 +14t +C we are not given an initial height so C is 0
h(t)=14t-gt^2/2 letting g=32 and neatening up a bit...
h(t)=14t-16t^2
Answer:
a. Variable term
b. Variable term
Explanation:
a) We were given the algebraic expression:

The first term of the algebraic expression is:

The first term is a variable term
The variable is "y" and its coefficient is "-5"
b) We were given the algebraic expression:

The second term of the algebraic expression is:

The second term is a variable term
The variable is "b" and the coefficient is "-6"